Answer:
2.28%
Step-by-step explanation:
Mr. bowens test is normally distributed with a mean (μ) of 75 and a standard deviation (σ) of 3 points.
The z score is used in probability to show how many standard deviation is a raw score below or above the mean. The formula for the z score (z) is given by:
For a raw score (x) of 81 points, the z score can be calculated by:
Therefore from the normal probability distribution table, the probability that a randomly selected score is greater than 81 can be given as:
P(x > 81) = P(z > 2) = 1 - P(z < 2) = 1 - 0.9772 = 0.0228 = 2.28%
Answer:
a) 6 ways
b) 6 ways
Step-by-step explanation:
a) for all of the letters
for the first letter, we have 3 options
for the second, we have 2 options
for the third, we have 1 option
So the number of options will be;
3 * 2 * 1 = 6
b) for the first, we have 3 options, for the second, we have 2 options
so the number of options will be 3 * 2 = 6 options
Answer is B Mr James
Lets convert all the fractions, percentages to decimals:_
Mr James: 5/8 = 0.625
Miss Smith: 0.61
Mrs Lawson: 9/16 = 0.5625
Mr Tosh: 0.58
Mrs Cagle 0.53
So Mr James corrected the most homework.
X=the man's age
500-2x=394
-500 -500
-2x=-106
-2x/2=-106/-2
x=53
FINAL ANSWER: 53 years old
Hope this helps! :)
The answers to the questions are:
1. The confidence level is 99 percent.
2. We have to conclude that there is no sufficient evidence available to support this claim because the Confidence interval contains 75 sec.
<h3>How to solve for the confidence level</h3>
1. The confidence level here should be
1- 0.01 = 0.99
= 99 percent
Given that, 99% confidence interval for population mean (μ) is (-34.1 sec u< u < 264.1 ) seconds.
We are to test the claim that the population mean is greater than 75 sec.
2.
The given confidence interval contains the value of 75 sec, so there is not sufficient evidence to support the claim that the mean is greater than 75 sec.
Read more on confidence interval here:
brainly.com/question/20309162
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