How did you write 917.27 in words

If you know how many CD's Mickey orders,can you determine how much money he spends?Write the correspondering expression.

Setler [38]

no not until u know the price of a cd u cant determine the total price

4 0

3 years ago

PLEASE HELO OK 1,3,4 ITS DUE TOMORROW

sukhopar [10]

#1. The number line goes by intervals of 0.2, so if A is equal to 7.28, then it’ll go in between the first line after 7 and the second line after 7. This is similar with B and C. B will go on the second line after 9, and C will go in between the second and third line after 10.

#3. You started out well. You combine your like terms on the sides of the equation to get 8x - 2 = 4x + 6. Then, you’ll subtract 4x to get 4x - 2 = 6. Add 2 to get 4x =8, then divide by 4 to get x = 2. On the other one, combine your terms to get -6 + 5y = 29. Then, add 6 so you have 5y = 35. Divide by 5 to get y = 7.

#4. When you classify a number, you need to classify it as whatever it is in your disgramdiagram, and the larger ones as well. For example, -2 is an integer, so it is also a rational number. 3/4 is a rational number. The square root of 2 over 2 is an irrational number. 292 is a counting, whole, integer, and rational number. -19/3 is a rational number. 6.9696... is an irrational number. (It has the three dots [...] so it’ll go on forever with no pattern.)

I hope this helps! Please tell me if you need any clarification. :)

3 0

3 years ago

Read 2 more answers

What is 35.6 × 10−4 in standard form?

Fittoniya [83]

$35.6\times10^{-4}=35.6\times0.0001=0.00356$

$a^{-n}=\dfrac{1}{a^n}\\\\10^{-4}=\dfrac{1}{10^4}=\dfrac{1}{10000}=0.0001$

8 0

2 years ago

If anyone could help?

Trava [24]

Answer:

$y=\frac{5}{7}x$ and $y=\frac{7}{9}x$

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In $y=\frac{5}{7}x$ when x=3, y=15/4≈2.14

In $y=\frac{3}{5}x$ when x=3, y=1.8

In $y=\frac{7}{9}x$ when x=3, y≈2.33

In $y=\frac{7}{11}x$ when x=3, y≈1.90

We can observe that in two cases, $y=\frac{5}{7}x$ and $y=\frac{7}{9}x$ , y is greater than 2.

5 0

2 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago

How did you write 917.27 in words​

How did you write 917.27 in words