D = 1/2 a t^2 is given. And it wants you to find t in terms if a and d. Which means, you need to arrange the equation and let t be alone.
If you let t^2 alone ;
2d/a = t^2
And square root t^2 will give you t ;
SquareRoot(2d/a) = t
The answer is (2)
Answer:
![[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]](https://tex.z-dn.net/?f=%5Bp-%7Cp%7C%2A10%5E%7B-3%7D%20%5C%2C%20%2C%20%5C%2C%20p%2B%7Cp%7C%2A%2010%5E-3%5D)
Step-by-step explanation
The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is
r = |p*-p|/|p|
we want r to be at most 10⁻³, thus
|p*-p|/|p| ≤ 10⁻³
|p*-p| ≤ |p|* 10⁻³
therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]
Answer:
Step-by-step explanation:
1- 3/4
2- 64
3- 18
4- 36
5- 10
6- 3/4
7- $4.70
8- <
9- =
10- =
ns +sb = 5.4 cm
sb = en so en can be plugged in for sb
therefor es = 5.4