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3 years ago

Does anyone know how to solve this inequality algebraic-ally:

2 answers:

7 0

Answer:

[-1/2,3]

Explanation:

Solve the Inequality by finding the roots and creating test intervals.

Note, the answer was provided in Intervals Notation form.

Snezhnost [94]3 years ago

3 0

Answer:

-1/2 ≤ x ≤ 3

Step-by-step explanation:

hope that helps

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Drew and Larry are working together on a jigsaw puzzle. Drew places 11 less than 3 times the number of pieces that Larry places.

seropon [69]

Answer:

Larry places 19 puzzles

Step-by-step explanation:

Step one:

given data

let the number of puzzles Larry places be x

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4 years ago

Please answer the question in the photo, thanks!

belka [17]

Answer:

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right )$

We rearrange the fractions as improper fractions for easier division as follows;

$2\dfrac{1}{3} = \dfrac{7}{3}$

$-3\dfrac{2}{3} = -\dfrac{11}{3}$

Therefore, we have;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}$

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

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3 years ago