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3 years ago

Does anyone know how to solve this inequality algebraic-ally:

2 answers:

7 0

Answer:

[-1/2,3]

Explanation:

Solve the Inequality by finding the roots and creating test intervals.

Note, the answer was provided in Intervals Notation form.

Snezhnost [94]3 years ago

3 0

Answer:

-1/2 ≤ x ≤ 3

Step-by-step explanation:

hope that helps

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Semielliptical Arch Bridge An arch for a bridge over a highway is in the form of half an ellipse. The top of the arch is 20 feet

photoshop1234 [79]

Answer:

the span of the bridge is 73.7 feet

Step-by-step explanation:

The equation of an ellipse with a vertical major axis(i.e major axis parallel to y axis) is given by:

$\frac{(x-h)^{2} }{b^{2} } + \frac{(y-k)^{2} }{a^{2} }= 1$ a>b

where (h,k) are the coordinates of the center of the ellipse, a is the length of the major axis and b is the length of the minor axis

For this problem, the center of the ellipse (h,k) = (0,0)

Therefore:

$\frac{(x)^{2} }{b^{2} } + \frac{(y)^{2} }{a^{2} }= 1$

The top of the arch is 20 feet above the ground level (the major axis), therefore a=20

length of the major axis = 2a= 2*20 = 40

$\frac{x^{2} }{b^{2} } + \frac{y^{2} }{20^{2} }= 1\\\frac{x^{2} }{b^{2} } + \frac{y^{2} }{400 }= 1$

The coordinates of the ellipse (x,y) = (28,13)

$\frac{28^{2} }{b^{2} } + \frac{13^{2} }{400 }= 1$

$\frac{28^{2} }{b^{2} } + 0.4225= 1$

$\frac{784 }{b^{2} } = 0.5775$

b² ≅ 1358

b≅36.85

Length of minor axis (2b) = 73.7 feet.

the span of the bridge is 73.7 feet

7 0

3 years ago

Which is TRUE about ALL expressions?

Zanzabum

Expressions do not have an equal sign (although they can have operators such as plus or minus).

$2x+1$ is an expression.

$2x+1=1$ is an equation since it has an equal sign.

8 0

3 years ago

Find the sum: -2.75+(-3.25)+5

dedylja [7]

The answer is -1. Hope this helps :)

7 0

3 years ago

Read 2 more answers

Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs

Roman55 [17]

Answer:

The area of the triangle is 18 square units.

Step-by-step explanation:

First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:

$AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}$

$AB \approx 7.616$

$BC = \sqrt{(-1-5)^{2}+(4-6)^{2}}$

$BC \approx 6.325$

$AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}$

$AC \approx 5.831$

Now we determine the area of the triangle by Heron's formula:

$A = \sqrt{s\cdot (s-AB)\cdot (s-BC)\cdot (s-AC)}$ (1)

$s = \frac{AB+BC + AC}{2}$ (2)

Where:

$A$ - Area of the triangle.

$s$ - Semiparameter.

If we know that $AB \approx 7.616$ , $BC \approx 6.325$ and $AC \approx 5.831$ , then the area of the triangle is:

$s \approx 9.886$

$A = 18$

The area of the triangle is 18 square units.

7 0

2 years ago

a student claims that 8 to the third power times 8 to the -5 power is greater than 1 explain whether the student is correct or n

nika2105 [10]

I think he is not correct because there is negative number so it can't be greater than one

7 0

3 years ago