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makvit [3.9K]
2 years ago
10

The ratio of boys to girls at a movie is 7:10. If there are 49 boys at the movie, then how many girls are at the movie?

Mathematics
1 answer:
jeka57 [31]2 years ago
3 0

Answer:

¯\_(ツ)_/¯

Step-by-step explanation:

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(30 points, will mark as brainliest) I need help with my algebra 1 homework, its open book so don't worry I can ask on here.
vichka [17]

Answer:

Step-by-step explanation:

2.

y=kx

8=-4k

k=-2

so y=-2x

3.

eq.~of~line~is~y-4=\frac{4-4}{1+3} =\frac{0}{4} =0\\or~y=4\\or~y=0 x+4

4.

eq. of  line is y-5=4(x+2)

3 0
3 years ago
Mr. Lowery has 8 3/4 pounds of ground beef that he will use to make hamburgers for a picnic. What is the maximum number of quart
maw [93]
If each burger is 1/4 th of a pound, he can make a maximum of 35 hamburgers

3 from the 3/4ths and 32 from the 8

32+3 = 35
3 0
3 years ago
is (-1/2 x + 6/7) - (7/2 x - 4/7) equivalent to -4 x + 2/7 ? use the properties of operations to justify your answer
LuckyWell [14K]

Answer:

The given equation is NOT justified.

Step-by-step explanation:

Here, the given equation is (\frac{-1}{2}x + \frac{6}{7} )  -  (\frac{7}{2}x - \frac{4}{7} )   = -4x + \frac{2}{7}

Now, here Consider the left hand side and simplifying the left side by operating on the like terms,

⇒(\frac{-1}{2}x + \frac{6}{7} )  -  (\frac{7}{2}x - \frac{4}{7} )   = \frac{-1}{2}x + \frac{6}{7}   -  \frac{7}{2}x + \frac{4}{7}  =  (\frac{-1}{2}x -\frac{7}{2}x) + (\frac{6}{7}   + \frac{4}{7})

=(\frac{-1 - 7}{2}x ) + (\frac{6 + 4}{7} ) = \frac{-8x}{2} + \frac{10}{7}   \neq -4x + \frac{2}{7}

Here, Left side of equation  ≠ Right side of the equation

Hence, (\frac{-1}{2}x + \frac{6}{7} )  -  (\frac{7}{2}x - \frac{4}{7} )   ≠ -4x + \frac{2}{7}

4 0
3 years ago
The triangles are similar by the AA similarity postulate find the value of x ?
Natasha_Volkova [10]
4/5 = (4 + 8)/x
4x = 5(12) = 60
x = 60/4 = 15
3 0
3 years ago
The perfect squares between 2 and 17.
postnew [5]

Answer:

4...9...16

Step-by-step explanation:

2^{2}=4

3^{2}=9

4^{2}=16

4 0
3 years ago
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