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3 years ago

A rectangle Is (2x-3) cm long and (x+7) cm wide. What Is It's area?

Mathematics

2 answers:

krok68 [10]3 years ago

6 0

Answer:

$2x^{2}$ + 11x -21 $cm^{2}$

Step-by-step explanation:

Area of a rectangle = Length × Width

= (2x-3)(x+7)

Multiply 2x with x, 2x with +7, -3 with x and -3 with +7

= $2x^{2}$ + 14x - 3x - 21

= $2x^{2}$ + 11x -21 $cm^{2}$

Nikitich [7]3 years ago

4 0

Answer:

Step-by-step explanation:

Length (L)= 2x - 3 cm

Breadth (b) = x + 7 cm

Area of the rectangle

= L * b

= ( 2x - 3)(x+ 7)

= 2x(x + 7) - 3(x + 7)

= 2x² + 14x - 3x - 21

=( 2x² + 11x - 21) cm²

hope it helps

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Mariana [72]

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ivann1987 [24]

Answer:

1 and 1/3

Step-by-step explanation:

3a² -4a +1 = 0

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2 years ago

The figure is the net for a rectangular prism.

svetoff [14.1K]

$sa = 2(lw + lh + wh)$

$sa = 2(8 \times 6 + 8 \times 16 + 6 \times 16)$

$sa = {544 \: cm}^{2}$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

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2 years ago

Read 2 more answers

Assume that the pond contains 90 fish: 64 purple, 25 green, and 1 red. A contestant pays $0.55 to randomly catch one fish and re

Licemer1 [7]

Answer:

The carnival is losing (on average) $0.15 on each play

Step-by-step explanation:

To find out how much the carnival wins or looses in each play one subtract the expected value (EV) from each play from the amount charged by the carnival for each play ($0.55). If the expected value is higher than what the carnival charges, the carnival is losing money.

Expected is the sum of the payouts of each bet multiplied by its likelihood:

$EV= \frac{64*0.40+25*1.15+1*9.00}{90}\\EV= 0.70$