Answer:
You add all these numbers then, divide the answer with 2.
Step-by-step explanation:
Trust
Answer:
98
Step-by-step explanation:
96+100=196
196÷2=98
Answer:
55°
Step-by-step explanation:
Let the centre of the circle be C
mFG=110 (It's hard to read but I assume thats what the 110 marks)
mFG=<FCG=110
Consider ΔFCG (an isosceles triangle since CF=CG=radius). Angles in a triangle add to 180 and <CFG=<CGF so <CFG=(1/2)(180-110)=(1/2)(70)=35°
<EFG+<CFG=90
<EFG+35=90
<EFG=55°
It is B, 5.64 because A and D can't fit on the number line and C is just not it because that would be one tick mark before 5.7
Answer:
a. We reject the null hypothesis at the significance level of 0.05
b. The p-value is zero for practical applications
c. (-0.0225, -0.0375)
Step-by-step explanation:
Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.
Then we have , , and , , . The pooled estimate is given by
a. We want to test vs (two-tailed alternative).
The test statistic is and the observed value is . T has a Student's t distribution with 20 + 25 - 2 = 43 df.
The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value falls inside RR, we reject the null hypothesis at the significance level of 0.05
b. The p-value for this test is given by 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.
c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)
, i.e.,
where is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So
, i.e.,
(-0.0225, -0.0375)