The solutions to system of equations are the point of intersection of the graphs of the equations.
The point of intersection of the graphs of the given equation is (0, 2). Therefore, point (1, 1) is not a solution to the system of equation.
Answer:
y = 6 or 8
Step-by-step explanation:
1. Subtract the constant:
y^2 -14y = -48
2. Add the square of half the y-coefficient:
y^2 -14y +49 = -48 +49
Write as a square, if you like:
(y -7)^2 = 1
3. Take the square root:
y -7 = ±√1 = ±1
4. Add the opposite of the constant on the left:
y = 7 ±1 = 6 or 8
The solution is y = 6 or y = 8.
Answer:
Option c
Step-by-step explanation:
A system of equations are given to us. And we need to solve them . The given system is
We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .
We got two values of x as 0 & 2 . Alternatively substituting these values we have ,
Thefore the required answer is ,
Solve for A
ab - ac = 2
First, you need to factorize
a(b - c) = 2
a= 2/(b -c)
