Answer : The value of equilibrium constant for this reaction at 262.0 K is 
Explanation :
As we know that,
where,
= standard Gibbs free energy = ?
= standard enthalpy = -45.6 kJ = -45600 J
= standard entropy = -125.7 J/K
T = temperature of reaction = 262.0 K
Now put all the given values in the above formula, we get:
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = -12666.6 J
R = gas constant = 8.314 J/K.mol
T = temperature = 262.0 K
K = equilibrium constant = ?
Now put all the given values in the above formula, we get:
Therefore, the value of equilibrium constant for this reaction at 262.0 K is
The correct answer is Platinum.
The metals which are not oxidized by an ion, they should be less reactive than silver, gold, and copper is platinum.
All group 11 elements are relatively corrosion-resistance metals and they are inert.
They have low electrical resistivity and are used for wiring. Copper, Silver, and gold are the most thermally conductive element and most light reflecting.
D to E
Is the answer that you're looking for
Answer:
I think the answer might be because Atomic mass is the weighted average of the naturally occuring isotopes. Also with the fact that it's not an integer, it would almost never be a whole number
Explanation:
