Answer:
Explanation:
Considering:
Given :
For NaOH :
Molarity = 0.0500 M
Volume = 45.88 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 45.88×10⁻³ L
Moles of NaOH = Moles of monoprotic acid
So, moles of monoprotic acid = 0.002294 moles
Given that:- mass = 0.456 g
The formula for the calculation of moles is shown below:
Thus,
Gaseous, meaning <span>relating to or having the characteristics of a gas</span><span>:
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Yes barium carbonate forms a ppt. it is insoluble in water
Answer:
Relative volume of ether to water that should be used for the extraction = 1.205
Explanation:
The extraction/distribution coefficient of an arbitrary solvent to water for a given substance is expressed as the mass concentration of the substance in the arbitrary solvent (C₁) divided by the mass concentration of the substance in water (C₂).
K = (C₁/C₂)
Let the initial mass of the organic substance X in water be 1 g (it could be any mass basically, it is just to select a right basis, since we are basically working with percentages here).
If 94% of the organic substance X is extracted by ether in a single extraction, 0.94 g ends up in ether and 0.06 g of the organic substance X that remains in water.
Let the volume of ether required be x mL.
Let the volume of water required be y mL.
Relative volume of ether to water that should be used for the extraction = (x/y)
Mass concentration of the organic substance X in ether = (0.94/x)
Mass concentration of organic substance X in water = (0.06/y)
The distribution coefficient , Ko (Cether / C water), for an organic substance X at room temperature is 13.
13 = (0.94/x) ÷ (0.06/y)
13 = (0.94/x) × (y/0.06)
13 = (15.667y/x)
(x/y) = (15.667/13) = 1.205
Hope this Helps!!!
