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lions [1.4K]
3 years ago
15

∆ABC is translated 2 units down and 1 unit to the left. Then it is rotated 90° clockwise about the origin to form ∆A′B′C′.

Mathematics
1 answer:
RideAnS [48]3 years ago
7 0

Answer:

The coordinates of image are A'(-2,1), B'(1,0) and C'(-1,0).

Step-by-step explanation:

From the figure it is clear that the coordinates of triangle are A(0,0), B(1,3) and C(1,1).

∆ABC is translated 2 units down and 1 unit to the left.

(x,y)\rightarrow (x-1,y-2)

A(0,0)\rightarrow (0-1,0-2)=(-1,-2)

B(1,3)\rightarrow (1-1,3-2)=(0,1)

C(1,1)\rightarrow (1-1,1-2)=(0,-1)

Then it is rotated 90° clockwise about the origin to form ∆A′B′C′.

(x,y)\rightarrow (y,-x)

(-1,-2)\rightarrow A'(-2,1)

(0,1)\rightarrow B'(1,0)

(0,-1)\rightarrow C'(-1,0)

Therefore the coordinates of image are A'(-2,1), B'(1,0) and C'(-1,0).

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