Point A(-7, 5) is reflected over x-axis.

Heights of Women. Heights of adult women are distributed normally with a mean of 162 centimeters and a standard deviation of 8 c

Bogdan [553]

Answer:

a) 6.68% of heights less than 150 centimeters

b) 58.65% of heights between 160 centimeters and 180 centimeters

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 162, \sigma = 8$

a) The percentage of heights less than 150 centimeters

We have to find the pvalue of Z when X = 150. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{150 - 162}{8}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

6.68% of heights less than 150 centimeters

b) The percentage of heights between 160 centimeters and 180 centimeters

We have to find the pvalue of Z when X = 180 subtracted by the pvalue of Z when X = 160.

X = 180

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{180 - 162}{8}$

$Z = 2.25$

$Z = 2.25$ has a pvalue of 0.9878

X = 160

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{160 - 162}{8}$

$Z = -0.25$

$Z = -0.25$ has a pvalue of 0.4013

0.9878 - 0.4013 = 0.5865

58.65% of heights between 160 centimeters and 180 centimeters

7 0

2 years ago

-3/4(4f - 2g) <br> Please answer as soon as you can!

torisob [31]

Answer:−

1

2

+

6

4

Step-by-step explanation:−

3

4

(

4

−

2

)

Simplify

1

Combine multiplied terms into a single fraction

−

3

4

(

4

−

2

)

−

3

(

4

−

2

)

4

2

Distribute

Solution

−

1

2

+

6

8 0

3 years ago

Can someone help me with 5 and 6? How do I put it? Will mark brainliest!

n200080 [17]

Answer:

5.

2 + 3 < y

6.

y + 2 ≥ 6

5 0

2 years ago

Read 2 more answers

An automobile manufacturer claims that its van has a 40.3 miles/gallon (MPG) rating. An independent testing firm has been contra

vovikov84 [41]

Answer:

The value of the test statistic is -2.64.

Step-by-step explanation:

The test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected(claimed) mean, $\sigma$ is the standard deviation and n is the size of the sample.

An automobile manufacturer claims that its van has a 40.3 miles/gallon (MPG) rating.

This means that $\mu = 40.3$

After testing 250 vans, they found a mean MPG of 39.9. Assume the standard deviation is known to be 2.4.

This means, respectively, that:

$n = 250, X = 39.9, \sigma = 2.4$

So

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{39.9 - 40.3}{\frac{2.4}{\sqrt{250}}}$

$t = -2.64$

The value of the test statistic is -2.64.

7 0

2 years ago

Why is a regression line referred to as the line of best fit?

aalyn [17]

<h2>Answer with explanation:</h2>

When there is a linear relationship is observed between the variables, we use linear regression predict the relationship between them.

Also, we predict the values for dependent variable by modelling a linear model that best fits the data by drawing a line Y=a+bX, where X is the explanatory variable and Y is the dependent variable.

In other words: The line of best fit is a line through a scatter plot of data points that best describes the relationship between them.

That's why the regression line referred to as the line of best fit.

4 0

3 years ago