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3 years ago

What is the distance between -5 and 4

Mathematics

1 answer:

Marysya12 [62]3 years ago

7 0

Answer:

Step-by-step explanation:

-5 , -4 , -3 , -2 , -1 , 0 , 1 , 2 , 3 , 4

-5 + 9 = 5

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Answer choices: A) 79 percent B) 57 percent C) 87 percent D) 81 percent

den301095 [7]

Answer:

right andlswer is D.) 81 degree

6 0

3 years ago

Please help and no links

Klio2033 [76]

Answer:

B) y=3x

Step-by-step explanation:

2 x 3 = 6

3 x 3 = 9

4 x 3 = 12

You can find y by multiplying the x by 3. The relationship between the x and y is proportional. For example, lets say my x is 20, my y would be 60. 20 x 3 = 60.

If you are still unsure, remember constant of proportionality is k=y/x, so your constant is 3.

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3 years ago

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Write an equation of each line that passes through the following points in slope-intercept form:

Firlakuza [10]

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3 years ago

Determine if the given function is a linear transformation. t(x1, x2, x3) = (−2x2, 6x3)

Zepler [3.9K]

$T:\mathbb R^3\to\mathbb R^2$ will be linear if for any $\mathbf x,\mathbf y\in\mathbb R^3$ and constants $a,b\in\mathbb R$ , we have

$T(a\mathbf x+b\mathbf y)=aT(\mathbf x)+bT(\mathbf y)$

Let $\mathbf x=(x_1,x_2,x_3)$ and $\mathbf y=(y_1,y_2,y_3)$ , and let $a,b$ be any two scalars. Then

$a\mathbf x+b\mathbf y=(ax_1+by_1,ax_2+by_2,ax_3+by_3)$

By definition of $T$ , we have

$T(a\mathbf x+b\mathbf y)=(-2ax_2-2by_2,6ax_3+6by_3)$
$T(a\mathbf x+b\mathbf y)=(-2ax_2,6ax_3)+(-2by_2,6by_3)$
$T(a\mathbf x+b\mathbf y)=a(-2x_2,6x_3)+b(-2y_2,6y_3)$
$T(a\mathbf x+b\mathbf y)=aT(\mathbf x)+bT(\mathbf y)$

Therefore $T$ is a linear transformation.

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3 years ago

Simplify -(3xy^4)^-4

Umnica [9.8K]

Answer:

$\frac{-1}{81x^4y^16}$