Subtract the sum of the expressions (4x2 – 6x + 3) and (-5x2 + 5x + 2) from the sum of (7x2 – 8x + 2) and (6x2

Need help solving this problem

Digiron [165]

2x^3+9, I just used an online calculator

7 0

3 years ago

HELP ME THIS MY LAST QUESTION PLEASE!!!!!!!!!!!!!!!!!!!!!!!

krok68 [10]

Answer: c

Step-by-step explanation:

7 0

3 years ago

There are 6 girls and 7 boys in a class. A team of 10 players is to be selected from the class. If the selection is random, what

Luden [163]

For the selection to be 10, there has to be at least 3 girls. So there's a 1/4 chance of 3 girls picked, 1/4 4 girls, 1/4 5 girls and 1/4 6 girls. Because the sum of people has to be 10, if 4 girls are picked, to make 10 people there is a 1/1 chance of 6 boys. 1/4 * 1/1 = 1/4. So 1/4 chance of 4 girls and 6 boys

7 0

3 years ago

Acertijo.

Cerrena [4.2K]

La edad de cada uno de los integrantes del acertijo es:

Luisa = 3 años 
Juan = 6 años 
Carmen = 8 años

Cálculo por medio de ecuaciones y el método de igualación.

Haciendo uso de la información brindada en el ejercicio, se procede a formular variables con las cuales se calcularán las ecuaciones, por lo tanto:

X = Edad de Luisa
Y = Edad de Juan
Z = Edad de Carmen

Con el enunciado: "Luisa es 3 años más joven que su hermano Juan" se crea la primera ecuación:

1. Y = X + 3

Con el enunciado: "Su hermana Carmen es 2 años mayor que Juan", se crea la segunda ecuación:

2. Z = Y + 2

Y con el enunciado: "Juan tiene el doble de edad que Luisa", se crea la tercera ecuación:

3. X = $\frac{Y}{2}$

Ahora, utilizando el método de igualación, se reemplaza la tercera ecuación en la primera:

Y = X + 3
Y = ( $\frac{Y}{2}$ ) + 3

Y se procede a sumar:

Y = ( $\frac{Y}{2}$ ) + 3
Y = $\frac{Y+6}{2}$

El dividendo se pasa al otro lado de la igualdad a multiplicar:

2Y = Y + 6

Y la variable "Y" que está sumando, se pasa al otro lado de la igualdad a restar:

2Y - Y = 6
Y = 6

Con el valor de Y (edad de Juan) se calcula X con la tercera ecuación:

X = $\frac{Y}{2}$
X = $\frac{6}{2}$
X = 3

Una vez calculado el valor de X (edad de Luisa), se procede a calcular el valor de Z con la segunda ecuación:

Z = Y + 2
Z = 6 + 2
Z = 8

Por lo tanto, se calcula que la edad de Luisa es 3 años, la edad de Juan es 6 años y la edad de Carmen es 8 años.

Más información sobre ecuaciones:

brainly.com/question/15415929?referrer=searchResults

8 0

3 years ago

A card is being drawn from a standard deck of playing cards. Find each probability.

EastWind [94]

These are 6 questions and 6 answers.

To find each probability we will use the definition of probability:

Probability = number of positive outcomes / number of total possible outcomes

1) P(Jack or ten)


Answer: 2/13 ≈ 0.12


Justification:

i) Positive outcomes: A standard deck of cards has 4 jacks and 4 tens, then those are 4 + 4 = 8 different positive outcomes.

ii) Possible outcomes: a standard deck of cards has 52 different cards, so, that is a total of 52 different possible outcomes

iii) Probability, P

P = number of positive outcomes / number of total possible outcomes

P = 8 / 52 = 2/13 ≈ 0.15

 2.P(red or black)


Answer: 1

Justification:

i) Positive outcomes

Half of the cards are red and half of the cards are black, so they both add for the total of the cards = 52

ii) Possible outcomes: 52 cards

iii) Probaility, P

P = number of positive outcomes / number of total possible outcomes

P = 52 / 52 = 1

 3.P(queen or club)


Answer: 4/13 ≈ 0.31

Justification:

i) Positive outcomes

There are 4 Queens.

There are 1/4 of 52 clubs = 1/4 × 52 = 13 clubs.

But you cannot add all of them, because one club is the Quenn of Clubs.

Then, the total number of different Queens and clubs is 4 + 13 - 1 = 16

ii) Possible outcomes: 52 different cards

iii) Probaility, P

P = number of positive outcomes / number of total possible outcomes

P = 16 /52 = 4 / 13 ≈ 0.31

 4.P(red or ace)


Answer: 7 / 13 ≈ 0.54

Justification:

i) Positive outcomes

Half of the cards are red: 26

There are 4 aces.

Since 2 aces are red, the number of different red and aces cards is: 26 + 4 - 2 = 28

ii) Possible outcomes: 52 different outcomes

iii) Probaility, P

P = number of positive outcomes / number of total possible outcomes

P = 28 / 52 = 7 / 13 ≈ 0.54

 5.P(diamond or black)


Answer: 1/2 = 0.5

Justification:

i) Positive outcomes

There are 52 / 4 = 13 diamonds

There are 26 black cards.

All the diamonds are black cards.

Then, the number of different diamond or black cards is 13 + 26 - 13 = 26

ii) Possible outcomes: 52 different cards.

iii) Probaility, P

P = number of positive outcomes / number of total possible outcomes

P = 26 / 52 = 1/2 = 0.5

6.P(face card or spade)

Answer: 11/26 ≈ 0.42

Justification:

i) Positive outcomes

Face cards are jacks, queens and kings. That is 3 × 4 = 12 different cards.

The spades are 13 cards.

Since, 3 of the faces are spade cards, the number of different cards of those types are 12 + 13 - 3 = 22

ii) Possible outcomes: 52 different cards

iii) Probaility, P

P = number of positive outcomes / number of total possible outcomes

P = 22 / 52 = 11 / 26 ≈ 0.42

4 0

3 years ago

Subtract the sum of the expressions (4x2 – 6x + 3) and (-5x2 + 5x + 2) from the sum of (7x2 – 8x + 2) and (6x2 – 3x + 8)