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3 years ago

Given u( – 5) = -5, u'( – 5) = 2, U( – 5) = 6, v'( – 5) = 4, find w'( – 5).

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

4 0

(a) w(x) = 5u(x) + 8v(x)

Differentiating with the sum rule gives

w'(x) = 5u'(x) + 8v'(x)

so that

w' (-5) = 5u' (-5) + 8v' (-5)

… = 5×2 + 8×4 = 42

(b) w(x) = u(x) v(x)

Differentiate using the product rule:

w'(x) = u'(x) v(x) + u(x) v'(x)

Then

w' (-5) = u' (-5) v (-5) + u (-5) v' (-5)

… = 2×6 + (-5)×4 = -8

(c) w(x) = u(x) / v(x)

Quotient rule:

w'(x) = (u'(x) v(x) - u(x) v'(x) ) / v(x) ²

Then

w' (-5) = (u' (-5) v (-5) - u (-5) v' (-5) ) / v (-5)²

… = (2×6 - (-5)×4) / 6² = 32/36 = 8/9

(d) w(x) = u(x) / (u(x) + v(x) )

Chain and quotient rule:

w'(x) = (u'(x) (u(x) + v(x)) - u(x) (u(x) + v(x))' ) / (u(x) + v(x) )²

… = (u'(x) (u(x) + v(x)) - u(x) (u'(x) + v'(x))) / (u(x) + v(x) )²

Then

w' (-5) = (u' (-5) (u (-5) + v (-5)) - u (-5) (u' (-5) + v' (-5))) / (u (-5) + v (-5) )²

… = (2×((-5) + 6) - (-5)×(2 + 4)) / ((-5) + 6)²

… = (2×1 + 5×6) / 1² = 32

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4) a) $y=-2x+7$

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Step-by-step explanation:

Exercise 3

$-3x + 5y = 2$

$\implies 5y = 3x + 2$

$\implies y=\dfrac35x+\dfrac25$

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If L2 passes through point (3, 1):

$y-y_1=m(x-x_1)$

$\implies y-1=-2(x-3)$

$\implies y=-2x+7$

So L2 = L1

b) If L3 is perpendicular to L1, then the slope of L3 is the negative reciprocals of the slope of L1 ⇒ $m = \dfrac12$

If L3 passes through point (-5, 2):

$y-y_1=m(x-x_1)$

$\implies y-2=\dfrac12(x+5)$

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3 years ago

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The state of New Jersey makes approximately $1.55 billion annually from tolls of the $1.55 billion about 3/4 comes from tolls on

Rama09 [41]

Percent of turn pike is 75% and percent of parkway is 25%.

Solution:

Given, The state of New Jersey makes approximately $1.55 billion annually from tolls of the $1.55 billion

About $\frac{3}{4}$ comes from tolls on the turnpike

Remaining $\frac{1}{4}$ comes from tolls on the parkway

To find the percent of the total revenue from turnpike:

$\begin{array}{l}{\text { Percent of turnpike }=\frac{\text { amount from parkway }}{\text { total revenue }} \times 100} \\\\ {=\frac{\frac{3}{4} \text { of total revenue }}{\text { tot al revenue }} \times 100} \\\\ {=\frac{\frac{3}{4} \times \text { total revenue }}{\text { total revenue }} \times 100} \\\\ {=\frac{3}{4} \times 100=3 \times 25=75 \%}\end{array}$

To find the percent of the total revenue from parkway:

$\begin{array}{l}{\text { Percent of parkway }=\frac{\text { amount from parkway }}{\text { total revenue }} \times 100} \\\\ {=\frac{\frac{1}{4} \text { of total revenue }}{\text { total revenue }} \times 100} \\\\ {=\frac{\frac{1}{4} \times \text { total revenue}}{\text { total revenue }} \times 100} \\\\ {=\frac{1}{4} \times 100=25 \%}\end{array}$

Summarizing the results:

Percent of turn pike is 75%

Percent of parkway is 25%

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4 years ago

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Given parameters:

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Unknown:

Selling cost this year = ?

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To solve this problem;

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irinina [24]

This is a great question for a calculator

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kozerog [31]

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