P=12T
Q=66T
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Toys added to each bag:
P=12T+nT
Q=66T+nT
Therefore, 66T+nT=3(12T+nT)
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66T+nT=36T+3nT
T(66+n)=T(36+3n)
66+n=36+3n
3n-n=66-36
2n=30
Therefore, n=30/2=15
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*She added 15 toys to each bag.
Answer:
i think its the third one
Step-by-step explanation: im srry if im wrong doe
I assume the heights are 160 ft and 1480 ft.
The two heights are unknown, so we will use variable h to help solve the problem.
The shorter building, building A, has height h.
Since building A is shorter by 160 ft, then building B is taller by 160 ft, so the height of building B is h + 160.
Now we add our two heights to find the total height.
h + h + 160 is the total height.
We can write it as 2h + 160
We are told the total height is 1480 ft, so we let 2h + 160 equal 1480, and we have an equation.
2h + 160 = 1480
Subtract 160 from both sides
2h = 1320
Divide both sides by 2
h = 660
h + 160 = 820
Building A measures 660 ft.
building B measures 820 ft.
Answer:
Step-by-step explanation:
The minimum (or min) of a set of numbers is the number with the smallest value in the set.
In this case, the smallest number in the set is 
.
