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shepuryov [24]
3 years ago
11

Help pls help me with this question

Mathematics
2 answers:
slavikrds [6]3 years ago
7 0

Answer:

E 16 cm

5cm + 5cm = 10cm

3cm + 3cm = 6cm

10cm + 6cm

= 16 cm

tangare [24]3 years ago
7 0

5×3=15 so 15 is your answer

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Write an equation to represent the following : 30 students can fit on a bus . If b buses are used and 3 students were left over
anzhelika [568]
30b+3= s

It would be thirty students times the number of buses, with an addition of 3 students equal to the total number of students when on the field trip.

I hope this helps!
~cupcake
6 0
3 years ago
What is 63 divided by 36?
katovenus [111]

Answer:

1.75

Step-by-step explanation:

used a calculator

8 0
3 years ago
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Quadrilateral ABCD is a square and the length of BE¯¯¯¯¯ is 6 cm.
SashulF [63]
BE = 6cm
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For a square, the diagonal are equal

so :::
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Done :)
6 0
4 years ago
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What is the sum of a 12-term arithmetic sequence where the last term is 13 and the common difference is -10?
Y_Kistochka [10]
\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=12\\
d=-10\\
a_{12}=13
\end{cases}
\\\\\\
a_{12}=a_1+(12-1)d\implies 13=a_1+(12-1)(-10)
\\\\\\
13=a_1-110\implies \boxed{123=a_1}

\bf \\\\
-------------------------------\\\\
\textit{sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n}{2}(a_1+a_n)\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
a_n=\textit{value of the }n^{th}\ term\\
------------\\
n=12\\
a_1=123\\
a_{12}=13
\end{cases}
\\\\\\
S_{12}=\cfrac{12}{2}(a_1+a_{12})\implies S_{12}=\cfrac{12}{2}(123+13)

and surely you know how much that is.
6 0
4 years ago
A half-marathon is 13.1 miles long. There is a water station every 1 1/3 miles along the race trail and at the finish line. How
pashok25 [27]

Answer:

10 water stations are needed

Step-by-step explanation:

To get the number of water- station needed, we simply divide the total length of the half marathon by the distance where we can find a water station

mathematically,

that would be 13.1 divided by 1 1/3

= 13.1 divided by 4/3

= 13.1 * 3/4 = 9.825 which is approximately 10

8 0
3 years ago
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