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shepuryov [24]
3 years ago
11

Help pls help me with this question

Mathematics
2 answers:
slavikrds [6]3 years ago
7 0

Answer:

E 16 cm

5cm + 5cm = 10cm

3cm + 3cm = 6cm

10cm + 6cm

= 16 cm

tangare [24]3 years ago
7 0

5×3=15 so 15 is your answer

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1) Give an example of a math formula.
nikitadnepr [17]

this is an example of a formula

y=mx+b

3 0
3 years ago
Please help me, due soon
antiseptic1488 [7]

Answer:

B. 21 and 19/25

Step-by-step explanation:

Rewrite the decimal number as a fraction with 1 in the denominator

21.76=21.761

Multiply to remove 2 decimal places. Here, you multiply top and bottom by 102 = 100

21.761×100100=2176100

Find the Greatest Common Factor (GCF) of 2176 and 100, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 4,

2176÷4100÷4=54425

Simplify the improper fraction,

=211925

In conclusion,

21.76=211925

8 0
2 years ago
Read 2 more answers
An author argued that more basketball players have birthdates in the months immediately following July​ 31, because that was the
Lady_Fox [76]

Answer:

There is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

Step-by-step explanation:

In this case we need to test whether there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

<em>H₀</em>: The observed frequencies are same as the expected frequencies.

<em>Hₐ</em>: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

 \chi^{2}=\sum{\frac{(O-E)^{2}}{E}}

The values are computed in the table.

The test statistic value is \chi^{2}=128.12.

The degrees of freedom of the test is:

n - 1 = 12 - 1 = 11

Compute the <em>p</em>-value of the test as follows:

p-value < 0.00001

*Use a Chi-square table.

p-value < 0.00001 < α = 0.05.

So, the null hypothesis will be rejected at any significance level.

Thus, there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

6 0
3 years ago
3/4^2 + 1^2 = x2<br><br> solve for x with work shown! pls help!
photoshop1234 [79]

Answer:

X=19/32

Step-by-step explanation:

3/4^2+1^2=2*x

3/4^2+1=2x

3+(4^2)/4^2=2x

3+16/4^2=2x

19/4^2=2x

19/(2^2)^2=2x

19=16(2x)

19=16*2x

32x=19

32x/32=19/32

x=19/32

This took alot of time goodluck!

8 0
2 years ago
Read 2 more answers
Find the midpoint of the segment below and enter its coordinates as an
o-na [289]

Answer:

(2,5)

Step-by-step explanation:

(X<em>m</em>, Y<em>m</em>)= ( (x1+x2)/2, (y1+y2)/2 )

= (5 + (-1))/ 2, (5+5)/2

= (4)/2, (10)/2

= 2, 5

3 0
2 years ago
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