Let
x---------> the length side of the rectangular area
y---------> the width side of the rectangular area
we know that
the area of the rectangle is equal to

-----> equation 
The perimeter of the rectangle is equal to

but remember that the fourth side of the rectangle will be formed by a portion of the barn wall
so
-----> equation 
<em>To minimize the cost we must minimize the perimeter</em>
Substitute the equation
in the equation 
![P=x+2*[\frac{200}{x} ]](https://tex.z-dn.net/?f=%20P%3Dx%2B2%2A%5B%5Cfrac%7B200%7D%7Bx%7D%20%20%5D%20)
Using a graph tool
see the attached figure
The minimum of the graph is the point 
that means for 
the perimeter is a minimum and equal to 
<u>Find the value of y</u>



The cost of fencing is equal to

therefore
<u>the answer is</u>
the length side of the the fourth wall will be 
16.55-16.56 depending on how you round
If 60% of a number is 75, we have to know the following:
60%=3/5.
3/5 of 75 is 45.
Therefore, 60% of 75 is 45.
Standard form is ax+by=c, we like a and b to be integers, we also like a to be positive
basically get x and y on one side
so
y-4=(3/4)(x+8)
distribte the 3/4
y-4=(3/4)x+6
minus 3/4x from both sides
-(3/4)x+y-4=6
add 4 to both sides
(-3/4)x+y=10
times both sides by -4
3x-4y=-40