20 is what present of 30?

Help please I will give brainliest

mestny [16]

D. 7/23 is your answer

8 0

3 years ago

Read 2 more answers

-3/7 is equivalent to what other fraction

liubo4ka [24]

Answer:

Step-by-step explanation:

6/14 = -9/21 = -12/28 = -15/35 = -18/42 = -21/49 = -24/56 = -27/63 = -30/70 = -33/77 = -36/84 = -39/91 = -42/98 = -45/105 = -48/112

6 0

3 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3>Solution:</h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

The area of rectangle is given as:

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

General form of quadratic equation is

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago

Given: AB = 4 AC = 6 What point is in the interior of both circles? H. A. B.

AleksAgata [21]

Answer:

Point A is in the interior of both circles

Step-by-step explanation:

Verify each point

we know that

Point H is in the interior of greater circle but is outside smaller circle

Point A is the center both circles, then is in the interior of greater circle and is in the interior of smaller circle

Point B is on the smaller circle and is in the interior of greater circle

therefore

Point A is in the interior of both circles

5 0

3 years ago

3. The values for p and q represent the equilibrium point. As related to the troupe's

svp [43]

Answer: The equilibrium point represents the raising or lowering the price in response to changes in the supply or demand.

If the price of a good is above equilibrium, this means that the quantity of the good supplied exceeds the quantity of the good demanded.

If the quantity is below the equilibrium point, it will create a shortage. because the quantity supplied is less than quantity demanded.

Hope this helps!

Step-by-step explanation:

5 0

2 years ago