Answer:
17 g Ba(NO₂)₂
General Formulas and Concepts:
<u>Chemistry</u>
- Stoichiometry
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
4.5 × 10²² molecules Ba(NO₂)₂
<u>Step 2: Define conversion</u>
Molar Mass of Ba - 137.33 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol
<u>Step 3: Dimensional Analysis</u>
<u />
= 17.1384 g Ba(NO₂)₂
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules.</em>
17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂
<span>Grid
The cathode serves as the positive terminal and the anode as the negative terminal. The flow of electrons is from the cathode to the anode.</span><span>The relationship between a cathode and an anode involves electrons. An example of this is reaction that takes place in an electrolytic cell. It has a cathode compartment, an anode compartment and a salt bridge that divides the compartment. The movement of electrons is from the cathode to the anode. </span>
<span>0.929 g/ml
Density in this case is defined as mass per volume. Or in other words, mass divided by volume. So you simply divide 929 grams by 1000 ml. Giving
929 g / 1000 ml = 929/1000 g/ml = 0.929 g/ml</span>
