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1 year ago

25.0cm3 of 0.10M sodium hydroxide solution is exactly neutralised by

Chemistry

1 answer:

Sergio [31]1 year ago

8 0

Answer:

25.00 cm 3 of 0.100 mol/dm 3 sodium hydroxide solution is exactly neutralised by 0.125 mol/dm 3 hydrochloric acid.

your answer is B

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How does a chemist count the number of particles in a given number of moles of a substance?

jolli1 [7]

The chemist the count the number of particles (Atoms, Molecules or Formula Unit) in a given number of moles of a substance by using following relationship.

Moles = # of Particles / 6.022 × 10²³

Or,

# of Particles = Moles × 6.022 × 10²³

So, from above relation it is found that 1 mole of any substance contains exactly 6.022 × 10²³ particles. Greater the number of moles greater will be the number of particles.

8 0

3 years ago

How many moles in 4.65 g of Helium?

Maru [420]

Answer:

4.65 g x 1 mol/4.0026 g/mol = 1.162 mol helium

Explanation:

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2 years ago

Which type of energy in the bungee cord prevents the bungee jumper from hitting the ground

Effectus [21]

Elastic potential energy

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3 years ago

Calculate the number of atoms in 5 moles H₂O.

oksano4ka [1.4K]

Answer:

90.35 × 10²³ atoms

Solution:

1 molecules of H20 contains 3 atoms,.

And we know that one mole of any molecule contains 6.023 × 10²³ atoms from Avogadro's number,

hence 5 moles of H20 will contain = 5× 6.023 × 10²³ × 3 atoms = 90.35 × 10²³ atoms!

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4 0

2 years ago

What volume of 0.152 M KMnO4 solution would completely react with 20.0 mL of 0.381 M FeSO4 solution according to the following n

ANEK [815]

Answer: The volume of permanganate ion (potassium permanganate) is 10.0 mL

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of ferrous sulfate solution = 0.381 M

Volume of solution = 20.0 mL = 0.020 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.381M=\frac{\text{Moles of ferrous sulfate}}{0.020L}\\\\\text{Moles of ferrous sulfate}=(0.381mol/L\times 0.020L)=0.00762mol$

For the given chemical equation:

$5Fe^{2+}+8H^++MnO_4^-\rightarrow 5Fe^{3+}+Mn^{2+}+4H_2O$

By Stoichiometry of the reaction:

5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

So, 0.00762 moles of iron (II) ions (ferrous sulfate) will react with = $\frac{1}{5}\times 0.00762=0.00152mol$ of permanganate ion (potassium permanganate)

Now, calculating the volume of permanganate ion (potassium permanganate) by using equation 1, we get:

Molarity of permanganate ion (potassium permanganate) = 0.152 M

Moles of permanganate ion (potassium permanganate) = 0.00152 mol

Putting values in equation 1, we get:

$0.152mol/L=\frac{0.00152mol}{\text{Volume of permanganate ion (potassium permanganate)}}\\\\\text{Volume of permanganate ion (potassium permanganate)}=\frac{0.00152mol}{0.152mol/L}=0.01L=10.0mL$

Hence, the volume of permanganate ion (potassium permanganate) is 10.0 mL

3 0

3 years ago