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34kurt
3 years ago
6

Andy and Charlie are riding on a merry go-round. Andy rides on a horse at the outer rim of the circular platform, four times as

far from the center of the circular platform as Charlie, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, which of the following best describes Andy's angular speed? PLEASE provide an explanation of your choice.
1) impossible to determine,
2) one-fourth of Charlie's,
3) four times Charlie's and
4) the same as Charlie's.
Physics
1 answer:
mestny [16]3 years ago
3 0

Answer:

4) the same as Charlie's.

Explanation:

They both make one full circuit (2π radians) of the merry go round in the same amount of time, therefore their angular speed is the same

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A bicyclist is riding to the left with a velocity of 14 \,\dfrac{\text m}{\text s}14 s m ​ 14, start fraction, start text, m, en
Gnesinka [82]

Answer:

-2.0 m/s²

Explanation:Acceleration is the rate of change of velocity.

\begin{aligned}a&=\dfrac{\text{Change in velocity}}{\text{Change in time}}\\ \\ &=\dfrac{v_f-v_i}{\Delta t} \end{aligned}

a

​

 

=

Change in time

Change in velocity

​

=

Δt

v

f

​

−v

i

​

​

​

Hint #22 / 3

We can calculate the bicyclist's acceleration from the final velocity v_fv

f

​

v, start subscript, f, end subscript, initial velocity v_iv

i

​

v, start subscript, i, end subscript, and time interval \Delta tΔtdelta, t.

\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

a

​

 

=

Δt

v

f

​

−v

i

​

​

=

3.5s

−21

s

m

​

−(−14

s

m

​

)

​

=−2.0

s

2

m

​

​

Hint #33 / 3

The acceleration of the bicyclist is -2.0\,\dfrac{\text m}{\text s^2}−2.0

s

2

m

​

minus, 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.

5 0
3 years ago
How much force is needed to accelerate a 1,100 kg car at a rate of 1.5 m/s2?
Anna [14]
Assuming there is no force of friction...

F = ma
F = (1300kg)(1.5m/s^2)
F = 1950N
Just multiply mass by acceleration.
1300 x 1.5 = 1950N.
7 0
3 years ago
What effect do impurities have on the crystal lattice? Why does that result in the lowering of the melting point of a solid?
s344n2d4d5 [400]

Answer:

It reduces the melting point due to a defect in the arrangement of the crystal lattice.

Explanation:

The presence of impurities creates a disorderliness in the uniformity of the crystal structure. It lowers the melting point by a few degrees because it becomes easier to overcome the intermolecular force of attraction.

It makes the array of crystals disordered.  

Lattice is a long chain three-dimensional arrangement of the molecules, atoms or ions in a crystal structure.

3 0
4 years ago
Please help it’s urgent!
mariarad [96]

(,I hope this helps yoy)

Explanation:

1.If the displacement of an object is zero,the speed must be zero.

Not true

2.(your answer is true)

3.false

4.true

4 0
3 years ago
An object of mass 20g taken at a height of 2m above the ground. Which type of energy is possessed by the object at this height ?
In-s [12.5K]
<h3><u>Given</u> </h3>
  • Mass of an object is \bf\red{20 g}
  • Height of the body is \bf\green{2 m}
<h3><u>To Find</u></h3>
  • Value of the energy

<h3><u>Solution</u></h3>

{\purple {\underline{\boxed{\sf{ Potential\: Energy \:=\: mgh}}}}}

Where,

  • \sf\red{m} = Mass
  • \sf\green{g} = Gravity
  • \sf\blue{h} = Height

Now, Converting gram to kg

\longrightarrow\: 1000g = 1kg

\longrightarrow\: 20g = \sf\dfrac{20}{1000}

\longrightarrow\: = 0.02 kg

According to the question

\sf\red{Mass \:= \:0.02 kg}

\sf\green{Gravitational \;force \:= \;10 m/s^{2}}

\sf\purple{Height\: =\: 2 m}

Putting these values

\to\: Potential Energy = mgh

\to\: Potential Energy = 0.02 × 10 × 2

\to\: Potential Energy = 0.2 × 2

\to\: Potential Energy = \bf\pink{0.4\:joules}

7 0
3 years ago
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