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3 years ago

How much force is needed to accelerate a 1,100 kg car at a rate of 1.5 m/s2?

1 answer:

7 0

Assuming there is no force of friction...

F = ma
F = (1300kg)(1.5m/s^2)
F = 1950N
Just multiply mass by acceleration.
1300 x 1.5 = 1950N.

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3 years ago

What's the difference and similarity between O2 and 2 O ?

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3 years ago

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2 years ago

During a workout, the football players at State U ran up the stadium stairs in 61 s. The stairs are 130 m long and inclined at a

NeTakaya

Answer:

P = 1097 Watt

Explanation:

given,

length of stairs, L = 130 m

inclination with horizontal,θ = 30°

mass of the football player = 105 Kg

time = 61 s

we know,

$Power = \dfrac{work}{time}$

Work = change in Potential energy

h = L sin 30°

h = 130 x 0.5

h = 65 m

W = m g h

W = 105 x 9.8 x 65

W = 66885 J

now,

$P = \dfrac{66885}{61}$

P = 1097 Watt

hence, the power output on the way is 1097 W

5 0

3 years ago

The pupil of an eagle’s eye has a diameter of 6.0 mm. Two field mice are separated by 0.010 m. From a distance of 185 m, the eag

max2010maxim [7]

Answer:

time is 5.973826 sec

Explanation:

Given data

diameter D = 6.0 mm 6× $10^{-3}$ m

separated d = 0.010 m

distance (dis) 185 m

speed s = 16 m/s

wavelength = 550 nm = 550 $10^{-9}$ m

to find out

How much time passes

solution

we know that for resolution we use Rayleigh's Criterion i.e

θ = 1.22 wavelength / diameter = separated / distance 1

we calculate distance 1 by put value wavelength, diameter and separated

distance 1 = diameter × separated / 1.22 wavelength

distance 1 = 6× $10^{-3}$ × 0.010 / 1.22 × 550 × $10^{-9}$

distance 1 = 89.418778

so time will be i.e = distance (dis) - distance 1 / speed

time = ( 185 - 89.418778) / 16

time = 5.973826 sec

time is 5.973826 sec

4 0

3 years ago