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algol [13]
3 years ago
10

As the space shuttle orbits the Earth, the shuttle and the astronauts

Physics
1 answer:
morpeh [17]3 years ago
7 0
The answer is B. Weightlessness
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Debby and Ben took different routes to travel from Point A to Point E. Debby took the route along A, B, C, D, and E. Ben took th
svetlana [45]

Answer:

Ben's average speed was twice Debby's average speed.

Explanation:

Ben covered a total distance of 16 miles (10+4+2) and Debby covered 8 miles (3+2+2+1) which is half of what Ben covered. As they both reached the place in the same amount of time it tells us Ben was faster.

4 0
3 years ago
Read 2 more answers
A mass of 0.4 kg hangs motionless from a vertical spring whose length is 0.95 m and whose unstretched length is 0.65 m. Next the
nexus9112 [7]

Answer:

Explanation:

spring constant of spring = mg / x

= .4 x 9.8 / ( .95 - .65 )

=13.07 N / m

energy stored in spring = 1/2 k x²

= .5 x 13.07 x ( 1.2 - .65 )²

= 1.976 J

Let it goes x m beyond its equilibrium position

Total energy at initial point

= 1.976 + 1/2 m v²

= 1.976 + .5 x .4 x 1.6²

= 2.488 J

energy at final point

= mgh + 1/2 k x²

.4 x 9.8 x  ( .55 + x ) + .5 x 13.07 x² = 2.488

6.535 x² + 2.156 + 3.92 x = 2.488

6.535 x² + 3.92 x - .332 = 0

x = .075 m

7.5 cm

4 0
3 years ago
A 12 volt battery in a motor vehicle is capable of supplying the starter motor with 150 A. It is noticed that the terminal volta
qwelly [4]

Answer:0.0133 \Omega

Explanation:

Given

Voltage=12 V

Current(I)=150 A

V_{terminal}=10 V

r_{internal}=\frac{\Delta V}{I}

r_{internal}=\frac{12-10}{150}

r_{internal}=\frac{2}{150}=0.0133 \Omega

4 0
3 years ago
No, this question isn't abt language arts, mathematics. Im asking u this <br> How are u doing? c:
nekit [7.7K]

Answer:

horrible, but how about you?

Explanation:

3 0
3 years ago
If the distance between two objects is increased by a factor of 3 (tripled), how will this affect Fg?
scoray [572]

Answer:

2. F g decreases to 1/9

Explanation:

The formula for calculating the Force of gravity between two masses separated by a distance is expressed as;

F = GMm/d² ... 1

If the distance is tripled, the new force will be;

F1 = GMm/(3d)²

F1 = GMm/9d² ... 2

Divide equation 1 by 2

F/F1 = GMm/d²÷GMm/9d²

F/F1 = GMm/d²×9d²/GMm

F/F1 = 1 * 9

F = 9F1

F1 = 1/9 F

<em>This means that the new force decreases to 1/9</em>

6 0
3 years ago
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