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3 years ago

Solve for d. 3+d<3−d

Mathematics

2 answers:

VashaNatasha [74]3 years ago

8 0

d < 0

add d to both sides of the inequality

3 + d + d < 3

3 + 2d < 3

subtract 3 from both sides

2d < 3 - 3

2d < 0 ⇒ d < 0

Ket [755]3 years ago

3 0

The answer to your question is d<0

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mestny [16]

Answer:

The slopes are

$m1=\dfrac{2}{5}, m2=-\dfrac{5}{2}$

Therefore, the equations are equations of Perpendicular Lines .

Step-by-step explanation:

Given:

$y=\dfrac{2}{5}\times x + 1$ ......................Equation ( 1 )

$5x+2y=-4\\\\\therefore y = \dfrac{-5}{2}\times x-2$ ..............Equation ( 2 )

To Find:

Slope of equation 1 = ?

Slope of equation 2 = ?

Solution:

On comparing with slope point form

$y=mx+c$

Where,

m = Slope

c = y-intercept

We get

Step 1.

Slope of equation 1 = m1 = $\dfrac{2}{5}$

Step 2.

Slope of equation 1 = m2 = $-\dfrac{5}{2}$

Step 3.

Product of Slopes = m1 × m2 = $\dfrac{2}{5}\times -\dfrac{5}{2}=-1$

Product of Slopes = m1 × m2 = -1

Which is the condition for Perpendicular Lines

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$m1=\dfrac{2}{5},m2=-\dfrac{5}{2}$

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3 years ago

Value of (–3/8) × (+8/15). A. 11/15 B. 11/23 C. –1/5 D. –1/3

svet-max [94.6K]

ANSWER

The correct answer is C

EXPLANATION

We want to find the value of

$- \frac{3}{8} \times \frac{8}{15}$

This is the same as:

$- \frac{3}{8} \times \frac{8}{3 \times 5}$

We cancel out the common factors to get:

$- \frac{1}{1} \times \frac{1}{1 \times 5}$

We simplify to get:

$- \frac{1}{5}$

The correct answer is C

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3 years ago

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Answer:

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