Answer:
The sample size is
Step-by-step explanation:
From the question we are told that
The margin of error is E = 1.5 seconds
The standard deviation is s = 4 seconds
Given that the confidence level is 97% then the level of significance is mathematically represented as
=>
Generally from the normal distribution table the critical value of is
Generally the sample size is mathematically represented as
=>
=>
Answer:
∠HGJ = 35°
Step-by-step explanation:
Although the question is somewhat incomplete, I have tried to reconstruct the question as much as possible to aid understanding (attached is the pictorial representation of the rhombus).
Firstly, it is important to note that rhombuses are parallelograms which have all sides equal and whose diagonals are perpendicular to each other. In addition to this, their diagonals bisect one other.
Mathematically, |EF| = |FG| = |GH| = |HE|
Another property which rhombuses have is that their opposite angles are equal.
Mathematically, ∠E = ∠G, ∠H = ∠F
The adjacent angles in a rhombus are supplementary. This means that the sum of angles closest to each other is 180°.
Mathematically, ∠E + ∠F = 180°, ∠F + ∠G = 180°, ∠G + ∠H = 180°,
∠H + ∠E = 180°
The question gave us ∠GHE and asked us to find ∠HGJ (denoted as θ in the picture attached). Note that ∠GHE means ∠H. That is, ∠GHE ⇒ ∠H
∠GHE or ∠H = 110°
From the properties of rhombuses (earlier stated), we know that adjacent angles in a rhombus are supplementary
Mathematically,
∠GHE + ∠FGH ⇒ 110° + ∠FGH = 180° ⇒ ∠FGH = 180° - 110°
∠FGH or ∠G = 70°
To calculate for ∠HGJ, we divide ∠FGH by 2, we have:
∠HGJ = ∠FGH ÷ 2 = 70° ÷ 2
∠HGJ = 35°
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Answer:
Emma's flight is farther from the airport
Step-by-step explanation:
Even without doing any detailed calculation, you can see on a graph that the larger turn Alice's flight makes keeps it closer to the airport.
Emma's flight is farther from the airport.
__
The distance can be calculated using the Law of Cosines. The angle of interest is the supplement of the turn angle. Since the leg distances are the same in each case, the only variable affecting the distance from the airport is the angle measure. Again, the larger the turn, the shorter the distance from the airport. If T is the turn angle, the distance is ...
d² = 100² +50² -2·100·50·cos(180° -T)
d² = 12500 +10000·cos(T) . . . . . . . using cos(180°-T) = -cos(T)
d = 100√(1.25+cos(T))
For Alice's 70° turn, the distance is ...
d = 100√(1.25+0.342) ≈ 126.18 mi
For Emma's 50° turn, the distance is ...
d = 100√(1.25 +0.643) ≈ 137.58 mi
Emma's flight is farther from the airport.
_____
The law of cosines formula is ...
c² = a² +b² -2ab·cos(C)
where triangle sides are lengths a, b, c and angle C is opposite side c.
