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3 years ago

Estimate the grade received on a test when 8 questions are answered correctly out of 40

Mathematics

2 answers:

Aleonysh [2.5K]3 years ago

5 0

Answer:

The correct answer is B. 20%

Scilla [17]3 years ago

5 0

Answer:

B. 20%

Step-by-step explanation:

You can multiply the fraction to get 40/200, then simplify it to get 20/100 or 20%.

Hope this helps! Let me know!

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Find the area of this parallelogram

Andrei [34K]

Answer:

84cm^2

Step-by-step explanation:

Area of a parallelogram is Base times Height

Area = BxH

plug in

B = 14

H = 6

7 0

3 years ago

Read 2 more answers

Evaluate the expression when c = 5 and d = 8 <br> d + 6c

solmaris [256]

Answer:

Step-by-step explanation:

6 times 5 =30

d=8

30+8-38

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2 years ago

It takes four steps to factor 48 – 3y 4 completely. Using complete sentences and the appropriate vocabulary, explain each of the

Nezavi [6.7K]

Answer:

3(2 - y)(2 + y)(4 + y²)

Step-by-step explanation:

48 - 3y⁴

Take 3 common:

3(16 - y⁴)

16 is 4² and y⁴ is (y²)²

3(4² - (y²)²)

Using a² - b² = (a - b)(a + b)

3(4 - y²)(4 + y²)

Again, 4 = 2²

3(2² - y²)(4 + y²)

3(2 - y)(2 + y)(4 + y²)

8 0

3 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$