Answer:
may be 13 I hope this is the right answer
Answer:
Perimeter: 4 * s
Area: S 2
Diagonal: s 2 \sqrt {2} 2
Area of square when diagonal is given = 1 2 × d 2 \frac {1} {2}\times d^ {2} 21 × d2
Step-by-step explanation:
We are trying to find the number that when added to 19, gives us less than 42. We can set up this simple inequality:
19 + x < 42
Now, subtract 19 from both sides:
x < 23
Our number can be anything less than 23.
