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nadezda [96]
3 years ago
5

4. Priya notices thet the pressure inside one of her car tyres is too low. She pumps up the tyre to a higher pressure. a) What h

appens to the number of particles in the car tyre? b) What happens to the distance between particles as pressure increase? c) One of the tyres gets a puncture(small hole) . What happens to the pressure inside the tyre?
Physics
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

a) the number of particles increases

b) average distance between them should decrease

c) the number of particles decreases, the pressure must also decrease

Explanation:

a) When the girl pumps to increase the pressure inside the tire she introduces more particles. Therefore the number of particles increases

b) as the volume of the tire does not change and there are more particles, the average distance between them should decrease

c) When a hole is opened, some of the particles inside the tire come out, so as the number of particles decreases, the pressure must also decrease

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The block has a weight of 75 lblb and rests on the floor for which μkμk = 0.4. The motor draws in the cable at a constant rate o
WINSTONCH [101]

The given question is incomplete. The complete question is as follows.

The block has a weight of 75 lb and rests on the floor for which \mu k = 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.

Determine the output of the motor at the instant \theta = 30^{o}.

Explanation:

We will consider that equilibrium condition in vertical direction is as follows.

           \sum F_{y} = 0

         N - W = 0

           N = W

or,      N = 75 lb

Again, equilibrium condition in the vertical direction is  as follows.

        \sum F_{x} = 0

       T_{2} - F_{k} = 0

         T_{2} = \mu_{k} N

                  = 0.4 \times 75 lb

                  = 30 lb

Now, the equilibrium equation in the horizontal direction is as follows.

         \sum F_{x} = 0

       T Cos (30^{o}) + T Cos (30^{o}) = T_{2}

          2T Cos (30^{o}) = T_{2}

    or,             T = \frac{T_{2}}{2 Cos (30^{o})}

                        = \frac{30}{2 Cos (30^{o})}

                        = \frac{30}{1.732}

                        = 17.32 lb

Now, we will calculate the output power of the motor as follows.

             P = Tv

                = 17.32 lb \times 6

                = 103.92 \times \frac{1}{550} \times \frac{hp}{ft/s}

                = 0.189 hp

or,             = 0.2 hp

Thus, we can conclude that output of the given motor is 0.2 hp.

3 0
3 years ago
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Which of the things below have matter? There is more than 1 answer.
JulijaS [17]

Answer:

car and a can

Explanation:

3 0
3 years ago
If 0.45 moles of potassium chloride are consumed completely and we start with twice as much silver fluoride, how many moles of s
yanalaym [24]
I think that should be D. because is will produced the silver chloride

6 0
3 years ago
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A person with normal vision can focus on objects as close as a few centimeters from the eye up to objects infinitely far away. T
Fittoniya [83]

Answer:

Explanation:

For a person suffering from nearsightedness, far point is 3.5 m . That means , an object beyond 3.5 m will not be clearly visible by the person . Ray of light coming from 3.5 m will be focussed on retina . For an object to be visible from infinity , ray of light coming from infinity should appear to be coming from 3.5 m . In other words , the object placed at infinity should form a virtual  image at 3.5 m . This can be done by concave lens.

u = ∝ ;  v  = 3.5

Using lens formula

\frac{1}{v} -\frac{1}{u} = \frac{1}{f}

\frac{1}{-3.5} -0 = \frac{1}{f}

f = - 3.5 m .

8 0
3 years ago
1. A 500 N force applied to a box at a 50 degree angle above the horizontal surface. Find the x and y
Alex777 [14]

Answer:

The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.

Explanation:

At first we present a figure describing the situation explained on statement, the x and y components of the force are determined by the following trigonometric expressions:

F_{x} = F\cdot \cos \alpha (1)

F_{y} = F\cdot \sin \alpha (2)

Where:

F - Magnitude of the force, measured in newtons.

\alpha - Direction of the force above the horizontal surface, measured in sexagesimal degrees.

If we know that F = 500\,N and \theta = 50^{\circ}, then the components of the force is:

F_{x} = (500\,N)\cdot \cos 50^{\circ}

F_{x} = 321.394\,N

F_{y} = (500\,N)\cdot \sin 50^{\circ}

F_{y} = 383.023\,N

The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.

7 0
3 years ago
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