Answer:
Mercury:
.85
pea
Venus:
2.1
gumball
Earth:
2.2
gumball
Mars:
1.2
marble
Uranus:
9
grapefruit
Neptune:
8.6
softball
Explanation:
I have no clue if I'm right but hopefully, I am
So the equation for angular velocity is
Omega = 2(3.14)/T
Where T is the total period in which the cylinder completes one revolution.
In order to find T, the tangential velocity is
V = 2(3.14)r/T
When calculated, I got V = 3.14
When you enter that into the angular velocity equation, you should get 2m/s
Answer:
a= 23.65 ft/s²
Explanation:
given
r= 14.34m
ω=3.65rad/s
Ф=Ф₀ + ωt
t = Ф - Ф₀/ω
= (98-0)×
/3.65
98°= 1.71042 rad
1.7104/3.65
t= 0.47 s
r₁(not given)
assuming r₁ =20 in
r₁ = r₀ + ut(uniform motion)
u = r₁ - r₀/t
r₀ = 14.34 in= 1.195 ft
r₁ = 20 in = 1.67 ft
= (1.667 - 1.195)/0.47
0.472/0.47
u= 1.00ft/s
acceleration at collar p
a=rω²
= 1.67 × 3.65²
a = 22.25ft/s²
acceleration of collar p related to the rod = 0
coriolis acceleration = 2ωu
= 2× 3.65×1 = 7.3 ft/s²
acceleration of collar p
= 22.5j + 0 + 7.3i
√(22.5² + 7.3²)
the magnitude of the acceleration of the collar P just as it reaches B in ft/s²
a= 23.65 ft/s²
The answer is C because the three metals that are magnetic are iron, nickel, and cobalt, and it is metal so it is a conductor of electricity.
Answer:
a) Magnitude of maximum emf induced = 0.0714 V = 71.4 mv
b) Maximum current through the bulb = 0.00793 A = 7.93 mA
Explanation:
a) The induced emf from Faraday's law of electromagnetic induction is related to angular velocity through
E = NABw sin wt
The maximum emf occurs when (sin wt) = 1
Maximum Emf = NABw
N = 1
A = 4 cm² = 0.0004 m²
B = 6 T
w = (284/60) × 2π = 29.75 rad/s
E(max) = 1×0.0004×6×29.75 = 0.0714 V = 71.4 mV
Note that: since we're after only the magnitude of the induced emf, the minus sign that indicates that the induced emf is 8n the direction opposite to the change in magnetic flux, is ignored for this question.
b) Maximum current through the bulb
E(max) = I(max) × R
R = 9 ohms
E(max) = 0.0714 V
I(max) = ?
0.0714 = I(max) × 9
I(max) = (0.0714/9) = 0.00793 A = 7.93 mA
Hope this Helps!!
