Good evening,
Answer:
x > 5
x ≤ 12
Step-by-step explanation:
Visualize as if the inequality symbols are equal signs and then solve it as you would for a normal equation, note if you divide by two negative numbers at all you then switch the sign.
On a number line, an inequality sign without the “equal to” is plotted with an open circe.
An inequality sign, with the “equal to” is plotted with a closed circle.
3x - 7> 8
Add seven on both sides, we do this because we want to eliminate the 7 from one side.
3x > 15
Divide both sides by 3, we do this because you want to get rid of the 3 from x.
x > 5
As for the second inequality.
Divide both sides by -3, as I mentioned earlier switch the side since we are dividing by two negative numbers.
x ≤ 12
For the greater than inequality x > 5, plot a open circle on 5 and draw the line going to the right.
For the less than or equal to inequality x ≤ 12, plot a closed cirlce on 12 and draw the line going to the left.
A unique trick is to graph the line based on the direction (right or left) the inequality symbol is pointing to.
Answer:
1. deli, bakery, dairy;
2. deli, dairy, bakery;
3. bakery, dairy, deli;
4. bakery, deli, dairy;
5. dairy, bakery, deli;
6. dairy, deli, bakery
Step-by-step explanation:
6 possibilities
The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
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Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
1e+6 is the amount of cubic CM (or one million 1000000)