Answer:
3, 5, 7
Step-by-step explanation:
1st number: (2k+1)
2nd number: (2k+3)
3rd number: (2k+5), k∈Z
3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)
3*(4k+4)=3+6k+15
12k+12=18+6k
6k=6
k=1
1st number: (2k+1) = 3
2nd number: (2k+3)=5
3rd number: (2k+5)=7
let's firstly, convert the mixed fraction to improper fraction, and then subtract.
![\bf \stackrel{mixed}{2\frac{3}{4}}\implies \cfrac{2\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{11}{4}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{11}{4}-\cfrac{2}{3}\implies \stackrel{\textit{our LCD will be 12}}{\cfrac{(3)11-(4)2}{12}}\implies \cfrac{33-8}{12}\implies \cfrac{25}{12}\implies 2\frac{1}{12}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%204%2B3%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B11%7D%7B4%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Ccfrac%7B11%7D%7B4%7D-%5Ccfrac%7B2%7D%7B3%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bour%20LCD%20will%20be%2012%7D%7D%7B%5Ccfrac%7B%283%2911-%284%292%7D%7B12%7D%7D%5Cimplies%20%5Ccfrac%7B33-8%7D%7B12%7D%5Cimplies%20%5Ccfrac%7B25%7D%7B12%7D%5Cimplies%202%5Cfrac%7B1%7D%7B12%7D)
8y^3+316
divide both sides by 4 (smallest divisable number) just say you tried to factor 2 and 3 and they weren't whole numbers and then you tried 4 and gave you the answer :)
4(2y^3+79)
Step-by-step explanation:
Flour needed to make birthday cakes = 2x
Flour needed to make holiday cakes = 1y = y
Maximum amount of Flour allowed = 20 (No more than 20)
Therefore
2x + y must not be more than 20

Hhhhhhhhahahahahahahahahahahaahabahahah 4.7