Answer:
T-C-A-T-T-A-A-G-G-G-C-A-G-T-T-C-G-A-G
Explanation:
A = T
C = G
and vice-versa
Answer:
50%
Explanation:
Let's assume that the allele "T" gives the normal phenotype while the recessive allele "t" imparts the disease and is lethal in homozygous condition. The genotype of each of the two carrier parents would be "Tt". A cross between Tt and Tt would give the progeny in the following genotype ratio=
Tt x Tt= 1/4 TT: 1/2 Tt: 1/4 tt
Therefore, 1/2 or 50% progeny would be the carrier for the Tay-Sachs disease.
What are the options on it? I could help
The dead organisms are recycled back by the activity of decomposing or decomposition. I hope this helps!