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Alborosie
4 years ago
5

Please please help me!!!!!!!

Mathematics
1 answer:
givi [52]4 years ago
4 0
Y= 2/3x + 2. Hope it helps
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WILL GIVE BRANILIEST PLEASE HELP I AM TIMED Which of the following represents the divisor and the dividend for the
Julli [10]

Answer:

I think its D.

6 0
4 years ago
10 1/4 x 3 3/5 what is the answer?
Harlamova29_29 [7]

Answer:

369/10

Step-by-step explanation:

10 1/4=41/4

3 3/5=18/5

----------------

(41/4)(18/5)=738/20

simplify

369/10

8 0
3 years ago
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Select the correct answer from each drop-down menu.
navik [9.2K]

Answer:

(0,1/5) and (1/9,0)

Step-by-step explanation:

3/5x +1/3y=1/15

To find intercepts, plug in 0

y-intercept: 3/5(0) + 1/3y=1/15

y=1/15*3 = 3/15 = 1/5 or 0.2

x-intercept: 3/5x + 1/3(0) = 1/15

3x=1/15*5/3

x=5/45= 1/9

3 0
3 years ago
Convert polar equation to rectangular coordinates θ = − (9π/ 2)
yan [13]
Visualize pi/2 as 90° on the unit circle. this has no real component, only imaginary. same for 3pi/2, or -pi/2 as shown in this equation:

- \frac{ \pi}{2}  = 0  -  i

as you move around the unit circle, you'll find that 9pi/2 is the same angle as pi/2.

Thus, the rectangular coordinates are:
- \frac{9\pi}{2}  =  0 -  i


7 0
3 years ago
The amount of money that college students spend on rent each month is usually between $300 and $600. However, there are a few st
Rudiy27
<span>The <u>correct answer</u> is:

A) median.

Explanation<span>:

When measuring the spread of this data, the first thing we note is that $1300 is an outlier; it is much, much different from the rest of the data. Therefore it has the potential to skew some measures of spread. For instance, the mean (not in this list) would be affected, since 1300 will raise the mean higher than it should be.

Since 1300 affects the mean, it also affects the standard deviation, which is the average distance each point is from the mean. Therefore standard deviation is not the best measure to use.

The range will be affected by this value as well, since this is the highest value; without it, the highest would be much less, which would make the range much less. Therefore range is not the best measure.

The interquartile range is not affected much by an outlier, but it is not usually a measure of spread that we use to describe values such as this.

We typically use the median to describe these values; since it is in the middle, it is not really affected by any outliers, and it is not a range from lowest to highest, such as the interquartile range (lowest quartile to highest quartile). Therefore median is the best measure.</span></span>
4 0
3 years ago
Read 2 more answers
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