(B.) I think I don’t know
The measurement of STR is 24 degrees
Answer:
In vertex form we have y = (x + 2)^2 - 10
Step-by-step explanation:
x^2+4x-6=0 is in standard form; we want it in the form y - k = a(x - h)^2.
Complete the square within x^2+4x-6=0
We get x^2 + 4x - 6 = 0 => x^2 + 4x + 4 - 4 - 6, or
y = (x + 2)^2 - 10
Comparing this to y = (x - h)^2 - 10, we see that the vertex is at
(h, k) : (-2, -10)
Answer:
8-x meters
Step-by-step explanation:
Both 64 and x^2 are perfect squares, since 64=(8)^2 and x^2=(x)^2.
Additionally, 16x is twice the product of the roots of 64 and x^2, since 16x=2(8)(x).
So we can use h the square of a difference pattern to factor:
a^2-2(a)(b)+b^2=(a-b)^2
In this case, a=8 and b=x:
(8)^2-2(8)(x)+(x)^2=(8-x)^2
In conclusion...
64-16x+x^2=(8-x)^2
So the side length of the square is 8-x meters.
Answer:
Mr. Webster's garden is greater than Ms. Turner's garden by 282 sq. yards.
Step-by-step explanation:
Representing the length of the garden by l and width of the garden by w.
For turner's garden, given that l= 24 yards and w= 17 yards.
As the area, A, of the rectangular garden having length l and width w is
So, the area of Ms. Turner's garden, = 24x17=408 sq. yards
For turner's garden, given that l= 5 yards and w= 138 yards.
So, by using equation (i),
the area of Mr. Webster's garden, = 5x138=690 sq. yards
Here,
, and
= 690-408= 282 sq. yards.
Hence, Mr. Webster's garden is greater than Ms. Turner's garden by 282 sq. yards.