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3 years ago

Im giving out brailyest

Mathematics

1 answer:

irina [24]3 years ago

4 0

I would go with answer B! but that’s just my opinion

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Given a rectangle with side lengths of and , what is its area?

maw [93]

B = 2x+4
H = 3x-5

A = bh
= (2x+4)(3x-5)
= (2x)(3x)+(2x)(-5)+(4)(3x)+(4)(-5)
= 6x^2 - 10x + 12x - 20
= 6x^2 + 2x - 20

So the answer is A (6x^2 + 2x - 20) (i think)

8 0

3 years ago

Read 2 more answers

What is Quadrilateral!?

deff fn [24]

Answer:

Hi, There! I'll be Happy to help you (っ◕‿◕)っ ♥

<h2>Question</h2>

What is Quadrilateral!?

<h2>Answer</h2>

a quadrilateral can be defined as a closed, two-dimensional shape that has four straight sides. ✔

Step-by-step explanation:

<h3>Here are examples of Quadrilaterals</h3>

The seven types of quadrilaterals are parallelogram, rhombus, kite, rectangle, trapezoid, square, and isosceles trapezoid. ✔

<h3>Properties</h3>

<em>The sides do not have to be the same length. Quadrilaterals have four sides, four vertices, and four interior angles that add up to 360</em>°✔

Therefore, I hope this helps! ツ

8 0

3 years ago

Using the following image, solve for x

emmainna [20.7K]

Answer:

x= -3

Step-by-step explanation:

2x+14= 8

2x= -6

x = -3

5 0

3 years ago

Read 2 more answers

g Suppose that the populationy(t)of a certain kind of fish is given by the logistic modely′= 3y−2y2(a) Solve the Bernoulli equat

Ksju [112]

Answer:

y = $\frac{3}{2 + 3Ce^{-3t} }$

Step-by-step explanation:

As given , y' = 3y - 2y²

⇒y' - 3y = -2y²

Divide by y² in the above equation

⇒ $\frac{y'}{y^{2} } - \frac{3y}{y^{2} } = -\frac{2y^{2} }{y^{2} }$

⇒ $\frac{y'}{y^{2} } - \frac{3}{y } = -2$ ........(1)

Now , let $\frac{1}{y}$ = u

⇒- $\frac{1}{y^{2} } \frac{dy}{dt} = \frac{du}{dt}$

⇒- $\frac{1}{y^{2} }y' = \frac{du}{dt}$

∴ equation (1) becomes

- $\frac{du}{dt}$ - 3u = -2

⇒ $\frac{du}{dt}$ + 3u = 2

It is a linear differential equation

Now,

Integrating factor = I.F = $e^{\int\limits {3} \, dt }$ = $e^{3t}$

∴ The solution becomes

u.(I.F) = $\int\limits {2.(I.F)} \, dt$ + C

⇒u.( $e^{3t}$ ) = $\int\limits {2.(e^{3t} )} \, dt$ + C

⇒u.( $e^{3t}$ ) = $\frac{2e^{3t} }{3}$ + C

⇒u = $\frac{2}{3} + Ce^{-3t}$

As $\frac{1}{y}$ = u

⇒ $\frac{1}{y}$ = $\frac{2}{3} + Ce^{-3t}$

⇒ y = $\frac{1}{\frac{2}{3} + Ce^{-3t} } = \frac{3}{2 + 3Ce^{-3t} }$

⇒ y = $\frac{3}{2 + 3Ce^{-3t} }$

6 0

3 years ago

Asey wants to buy some instruments for his niece and nephew. He has $40 to spend. Based on the prices listed below, what is the

andrew-mc [135]

Answer:

I would pick a, the estimated total to the nearest dollar is 38

Step-by-step explanation:

13.95 rounded is 14

23.50 rounded is 24

24+14=38

7 0

2 years ago