What is an equation of the line that passes through the point (6,-4) and is perpendicular to the line 2x-y=5
1 answer:
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Answer:
y = - 2x - 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m =
with (x₁, y₁ = (- 2, 2) and (x₂, y₂ ) = (1, - 4)
m = =
= - 2, thus
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (- 2, 2), then
2 = 4 + c ⇒ c = 2 - 4 = - 2
y = - 2x - 2 ← equation of line