Serting a header at the top of a page will make it appear on____

Is the ipv6 address 2001:1d5::30a::1 a valid address? why or why not?

defon

<span>Not a valid IPv6 address A valid IPv6 address consist of 8 groups of 4 hexadecimal numbers separated by colons ":". But that can make for a rather long address of 39 characters. So you're allowed to abbreviate an IPv6 address by getting rid of superfluous zeros. The superfluous zeros are leading zeros in each group of 4 digits, but you have to leave at least one digit in each group. The final elimination of 1 or more groups of all zeros is to use a double colon "::" to replace one or more groups of all zeros. But you can only do that once. Otherwise, it results in an ambiguous IP address. For the example of 2001:1d5::30a::1, there are two such omissions, meaning that the address can be any of 2001:1d5:0:30a:0:0:0:1 2001:1d5:0:0:30a:0:0:1 2001:1d5:0:0:0:30a:0:1 And since you can't determine which it is, it's not a valid IP address.</span>

6 0

3 years ago

For this lab you will write a class to create a user-defined type called Shapes to represent different shapes, their perimeters

maw [93]

<h2>Answer:</h2>

<u />

========= Shape.java ===========

//import the Scanner class

import java.util.Scanner;

public class Shape{

//required fields

private String shape;

private double area;

private double perimeter;

//default constructor

public Shape(){

this.shape = "unknown";

this.area = 0.0;

this.perimeter = 0.0;

}

//constructor with one parameter

public Shape(String shape){

this.setShape(shape);

this.area = 0.0;

this.perimeter = 0.0;

}

//accessors and mutators

public void setShape(String shape){

this.shape = shape;

}

public String getShape(){

return this.shape;

}

public double getPerimeter(){

return this.perimeter;

}

public double getArea(){

return this.area;

}

public void setPerimeter(Scanner scr){

if(this.getShape().equals("circle")){

System.out.println("Enter the radius of the circle");

double radius = scr.nextDouble();

this.perimeter = 2 * 3.142 * radius;

}

else if(this.getShape().equals("rectangle")){

System.out.println("Enter the width");

double width = scr.nextDouble();

System.out.println("Enter the height");

double height = scr.nextDouble();

this.perimeter = 2 * (width + height);

}

else if(this.getShape().equals("square")){

System.out.println("Enter the height or width");

double height = scr.nextDouble();

this.perimeter = 4 * height;

}

else if(this.getShape().equals("unknown")){

System.out.println("You must define a shape first before calculating perimeter");

this.perimeter = 0.0;

}

else {

System.out.println("You must define a shape first before calculating perimeter");

this.perimeter = 0.0;

}

public void setArea(Scanner scr){

if(this.getShape().equals("circle")){

System.out.println("Enter the radius of the circle");

double radius = scr.nextDouble();

this.area = 3.142 * radius * radius;

}

else if(this.getShape().equals("rectangle")){

System.out.println("Enter the width");

double width = scr.nextDouble();

System.out.println("Enter the height");

double height = scr.nextDouble();

this.area = width * height;

}

else if(this.getShape().equals("square")){

System.out.println("Enter the height or width");

double height = scr.nextDouble();

this.area = height * height;

}

else if(this.getShape().equals("unknown")){

System.out.println("You must define a shape first before calculating area");

this.area = 0.0;

}

else {

System.out.println("You must define a shape first before calculating area");

this.area = 0.0;

}

//Own methods

//1. Method to show the properties of a shape

public void showProperties(){

System.out.println();

System.out.println("The properties of the shape are");

System.out.println("Shape : " + this.getShape());

System.out.println("Perimeter : " + this.getPerimeter());

System.out.println("Area : " + this.getArea());

}

//2. Method to find and show the difference between the area and perimeter of a shape

public void getDifference(){

double diff = this.getArea() - this.getPerimeter();

System.out.println();

System.out.println("The difference is " + diff);

}

========= ShapeTest.java ===========

import java.util.Scanner;

public class ShapeTest {

public static void main(String [] args){

Scanner scanner = new Scanner(System.in);

// create an unknown shape

Shape shape_unknown = new Shape();

//get the shape

System.out.println("The shape is " + shape_unknown.getShape());

//set the area

shape_unknown.setArea(scanner);

//get the area

System.out.println("The area is " + shape_unknown.getArea());

//set the perimeter

shape_unknown.setPerimeter(scanner);

//get the perimeter

System.out.println("The perimeter is " + shape_unknown.getPerimeter());

// create another shape - circle

Shape shape_circle = new Shape("circle");

//set the area

shape_circle.setArea(scanner);

//get the area

System.out.println("The area is " + shape_circle.getArea());

//set the perimeter

shape_circle.setPerimeter(scanner);

//get the area

System.out.println("The perimeter is " + shape_circle.getArea());

//get the properties

shape_circle.showProperties();

//get the difference between area and perimeter

shape_circle.getDifference();

}

<h2>Sample output:</h2>

The shape is unknown

You must define a shape first before calculating area

The area is 0.0

You must define a shape first before calculating perimeter

The perimeter is 0.0

Enter the radius of the circle

>> 12

The area is 452.448

Enter the radius of the circle

>> 12

The perimeter is 452.448

The properties of the shape are

Shape : circle

Perimeter : 75.408

Area : 452.448

The difference is 377.03999999999996

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining important parts of the code. Please go through the code for more explanations. For better formatting, the sample output together with the code files have also been attached to this response.

Download java

5 0

3 years ago

What is a problem? Give an example of abusiness problem and discuss how acomputer-based information system couldsolve it.

Naily [24]

Answer:

A problem is a challenging task or process that needs resources not available to the individual or group responsible for the task.

An example of a business problem is data analysis.

Explanation:

A business enterprise is driven by profit making. Investing in a business opportunity requires or demands for feasibility study. Without the right computer skills, a company dives into various physical forms of survey like giving questionnaires to potential clients.

This form of survey requires a lot of time and money that should be invested in other assets in the company and the data acquired, sometimes is not enough to make long term business decisions.

On the other hand, when a spreed sheet application is used (like microsoft excel) by a business data analyst with big data and data visualization skills, large data could be accessed online and analysed of a fast and efficient descriptive and predictive analysis for long term business decisions.

7 0

3 years ago

What is one effect the internet has had on the library

Shkiper50 [21]

Answer:

The internet provides access to an abundance of information from home, making it easier for people to get answers much faster. This efficiency has caused libraries to receive less business and less users, therefore making their service less popular.

7 0

3 years ago

Subtract (100000)2 from (111)2 using 1s and 2s complement method of subtraction

GenaCL600 [577]

Answer:

-11001

Explanation:

The following steps are performed in order to perform subtraction of the given binary numbers:

Step 1:

Find 2’s complement of the subtrahend. The subtrahend here is 100000

100000

First take 1's complement of 100000

1's complement is taken by inverting 100000

1's complement of 100000 = 011111

Now takes 2's complement by adding 1 to the result of 1's complement:

011111 + 1 = 100000

2's complement of 100000 = 100000

Step 2:

Add the 2's complement of the subtrahend to the minuend.

The number of bits in the minuend is less than that of subtrahend. Make the number of bits in the minuend equal to that of subtrahend by placing 0s in before minuend. So the minuend 111 becomes:

000111

Now add the 2's complement of 100000 to 000111

0 0 0 1 1 1

1 0 0 1 1 1

The result of the addition is :

1 0 0 1 1 1

Step 3:

Since there is no carry over the next step is to take 2's complement of the sum and place negative sign with the result as the result is negative.

sum = 1 0 0 1 1 1

2's complement of sum:

First take 1's complement of 1 0 0 1 1 1

1's complement is taken by inverting 1 0 0 1 1 1

1's complement of 1 0 0 1 1 1 = 0 1 1 0 0 0

Now takes 2's complement by adding 1 to the result of 1's complement:

0 1 1 0 0 0 + 1 = 0 1 1 0 0 1

Now place the minus sign with the result of 2's complement:

- 0 1 1 0 0 1

Hence the subtraction of two binary numbers (100000)₂ and (111)₂ is

(-011001)₂

This can also be written as:

(-11001)₂

6 0

3 years ago

Serting a header at the top of a page will make it appear on_____. ?