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algol13
3 years ago
7

It says graph ×< 1 btw​

Mathematics
1 answer:
Ymorist [56]3 years ago
6 0
Start at 1 and drag it towards the end of the negative side :)
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A pool pass costs $30 for the first month and $15 each additional month. Construct an explicit rule in function notation to mode
noname [10]

Answer:

F(n)=15(n+1)    [ where n is number of months]

F(12)=195

Step-by-step explanation:

Pool pass cost for first month =$30

Pool pass cost after first month = $15 for each month

The total amount charged by the pool can be expressed as a  function F(n) where n represents the number of months.

F(n)=15(n-1)+30

This can be simplified by using distribution.

F(n)=(15n-15)+30

F(n)=15n-15+30

F(n)=15n+15

Take 15 as greatest common factor.

∴ F(n)=15(n+1)

For n=12

F(12)=15(12+1)

F(12)=15(13)

F(12)=195

∴ Amount charged by pool for 12 months = $195

4 0
3 years ago
Carlotta handpaints T-shirts and sells them to her friends. She uses the equations below to determine her costs and the amount o
spayn [35]
Profit = Income - cost
Profit = 10s - (28 + 3s) = 10s - 28 -3s = 7s - 28.

Profit = 0

0 = 7s - 28

7s = 28
7s = 28/7
s = 4. This is the breakeven point.

Carlota must sell more than 4 shirts to make a profit
8 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST CAR!!!! HELP
Digiron [165]

Answer:

111°

Step-by-step explanation:

Let the centre of the circle be C

mRQ=157 (marked)

The angle at the centre of a circle standing on an arc is twice any angle at the circumference, standing on the same arc. So <SCR=2(SQR)=2(46)=92. mSR=<SCR=92

All the arc measure add up to 360 so:

mSQ+mRQ+mSR=360

mSQ+157+92=360

mSQ=360-249=111

4 0
4 years ago
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discha
mr Goodwill [35]

Answer:

Step-by-step explanation:

Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by

T(x) = 160-0.05x^2

a. [0, 10]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

The average temperature

= (160 + 155)/2 = 157.5

b. [10, 40]

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (80 + 155)/2 = 117.5

c. [0, 40]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (160 + 80)/2 = 120

6 0
3 years ago
Please help thank you ;)
Alexxx [7]

Answer:

the total angles shoudl add up to 180 but the angles listed adds up to 190 degreees

Step-by-step explanation:

<h2><em><u>This is not a real triangle</u></em></h2><h2><u>no triange</u></h2><h2><u>BBBBBBBB</u></h2>

I want brainliest!

3 0
4 years ago
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