The solution of the inequality is -8 ≥ b, and the correct graph is the one in option D.
"number line with a closed circle plotted at negative eight and arrow pointing left."
<h3>
How to solve the inequality?</h3>
Here we have the inequality:
-0.8*b + 2.3 ≥ 8.7
And we want to solve this, to do so, we need to isolate the variable b in one of the sides of the inequality.
-0.8*b + 2.3 ≥ 8.7
2.3 - 8.7 ≥ 0.8*b
-6.4 ≥ 0.8*b
-6.4/0.8 ≥ b
-8 ≥ b
So the solution is the set of all numbers equal to or smaller than -8, then the correct graph will be the one described by D.
Learn more about inequalities:
brainly.com/question/24372553
#SPJ1
Answer:
Step-by-step explanation:
Line d slope is 8/7, therefore the perpendicular is -7/8
Answer:
Answer is below
Step-by-step explanation:
Add 9 to both sides.
Divide both sides by 6
Answer/Step-by-step explanation:
Recall: SOHCAHTOA
1. Reference angle = 70°
Adjacent side = x
Hypotenuse = 6 cm
Apply CAH. Thus,
Cos 70 = adj/hyp
Cos 70 = x/6
6 × cos 70 = x
2.05 = x
x = 2.05 cm
2. Reference angle = 45°
Adjacent side = x
Hypotenuse = 1.3 m
Applying CAH, we would have the following ratio:
Cos 45 = adj/hyp
Cos 45 = x/1.3
1.3 × cos 45 = x
0.92 = x
x = 0.92 m
3. The who diagram is not shown well. Some parts are missing, however you can still solve the problem just the same way we solved problem 1 and 2.
Answer:
I think its right
Step-by-step explanation:
a) In the long run, we have, 5k=10 and k=2l Thus, C=2l+3l= 5l=0.5q Thus, AC=5l/10l =0.5 MC=0.5 b) In the short run, k=10 Q=min(50,10l) If l<5, q=10l. C=10+3l= 10+0.3q Thus, AC=10/q + 0.3 If l>5, q=50. C= 10+3l AC= (10+3l)/50 If q>50, then MC...
