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3 years ago

What is a root of a polynomial function?

Mathematics

1 answer:

lapo4ka [179]3 years ago

5 0

values of the variable that cause the polynomial to evaluate to zero.

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Which of the following is most likely the next step in the series ?

GalinKa [24]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Which of the following is most likely the next step in the series ?

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

The next series is most probably going to be option D. 
We can see from the series that, figure 1 has 4 points marked on the circle from which they formed a rectangle.
In the next figure, there are 3 points marked which together when joined forms a triangle.
Then the next circle has 2 points marked on it which makes a straight line.
So, obviously the next figure/circle in the series should have only 1 point marked on it. This won't form anything as you can't join just 1 point with something.

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3 years ago

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Paul has 27 pet cats. 14 of them are short-haired. 11 of them are kittens. 5 of them are long haired adult cats. How many of the

Oksanka [162]

I believe there are 3 short haired kittens, but let me know if I am wrong.

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3 years ago

5y+1=1 Subtract 1 from both sides

maks197457 [2]

Step-by-step explanation:

$5y + 1 = 1 \\ subtracting \: 1 \: from \: both \: sides \\ \red{ \boxed{ \bold{ 5y + 1 - 1 = 1 - 1}}} \\ 5y = 0 \\ y = 0$

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3 years ago

What is the slope of the line

mrs_skeptik [129]

Answer:steepness

Step-by-step explanation:

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3 years ago

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Simplify 1+sinx/cosx+cosx/1+sinx

Dmitry [639]

$\frac{1 + sin(x)}{cos(x)} + \frac{cos(x)}{1 + sin(x)}$
$\frac{[1 + sin(x)][1 +sin(x)]}{cos(x)[1 + sin(x)]} + \frac{cos(x)[cos(x)]}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + 1}{cos(x)[1 + sin(x)]}$
$\frac{1 + 1 + 2sin(x)}{cos(x)[1 + sin(x)]}$
$\frac{2 + 2sin(x)}{cos(x)[1 + sin(x)]}$
$\frac{2[1 + sin(x)]}{cos(x)[1 + sin(x)]}$
$\frac{2}{cos(x)}$
$2sec(x)$

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3 years ago