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3 years ago

Increasing temperature increases the number of collisions and the potential energy of the colliding molecules and

1 answer:

3 0

Increasing temperature does increase the amount of collision but it increases the kinetic energy of the molecules not the potential energy. Potential energy brings molecules together or apart (depending) and kinetic energy makes the molecules move around or not. Hope this helps

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1) List the number of protons, neutrons, and electrons in Carbon-13.

ser-zykov [4K]

1) Carbon-13:
Proton-6 Neutron-7 Electron-6

2)Atomic mass of element X:
(55*10+56*20+57*70)/100=56.6

4 0

4 years ago

What is the mass of alliminum?

Gennadij [26K]

Answer:

26.981539 u

Atomic number: 13

Symbol: Al

Electron configuration: [Ne] 3s²3p¹

5 0

3 years ago

Read 2 more answers

Which system includes feet, pounds, gallons, and miles?<br><br> metric <br><br> customary

slavikrds [6]

Answer:

customary Is the required system

3 0

3 years ago

Write Qc for each of the following:(1) Gaseous sulfur tetrafluoride reacts with liquid water to produce gaseous sulfur dioxide a

snow_tiger [21]

Answer : The expression for reaction quotient will be :

(1) $Q_c=\frac{[SO_2][HF]^4}{[SF_4]}$

(2) $Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}$

Explanation :

Reaction quotient $(Q_c)$ : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

(1) The given balanced chemical reaction is,

$SF_4(g)+2H_2O(l)\rightarrow SO_2(g)+4HF(g)$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted. So, the expression for reaction quotient will be :

$Q_c=\frac{[SO_2][HF]^4}{[SF_4]}$

(2) The given balanced chemical reaction is,

$2MoO_2(s)+XeF_2(g)\rightarrow 2MoF(l)+Xe(g)+2O_2(g)[/texIn this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted. So, the expression for reaction quotient will be :[tex]Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}$

7 0

3 years ago

500.0 mL of a gas is collected at 745.0 mm Hg. what what will the volume be at standard pressure

Irina-Kira [14]

This is an application of Boyle's law:
P₁V₁ = P₂V₂. we don't have to convert volume and pressure to standard forms. we can even use the pressure with mmHg
1 atm = 760 mmHg
V₂ = P₁V₁ / P₂ = 745 x 500 / 760 = 490 ml
Note that here we assume constant temperature

6 0

4 years ago