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dybincka [34]
3 years ago
15

I need help ASAP please

Chemistry
1 answer:
Andrej [43]3 years ago
3 0

525L

Explanation:

Given parameters:

Volume to Temperature ratio = 1.75

Temperature = 300k

Unknown:

Volume of the gas = ?

Solution:

We must carefully analyze and comprehend the detailed description of this experiment:

 It was suggest that the gas could expand or shrink without changing the pressure of the gas inside.

This implies that the pressure in the vessel is constant

This similar to the postulate of the Charles's law: The volume of a fixed mass of gas is directly proportional to the absolute temperature if the pressure is constant.

 Mathematically;

                 \frac{V1}{T1}  = \frac{V2}{T2}

V and T are the volume and temperature

 Now we can solve the given problem;

           \frac{V}{T}  = 1.75

Since temperature is given as 300K

 Input the variables:

           \frac{V}{300}  =  1.75

          V = 1.75 x 300 = 525L

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

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If 125g of KClO3 is heated, what is the total mass of the products?​
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Given parameters:

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Unknown:

Total mass of the products = ?

When  KClO₃ is heated, it thermally decomposes to KCl and O₂ according to the chemical equation below;

               2KClO₃  →  2KCl + 3O₂

All chemical equations obeys the law of conservation of matter and with this regard, we know that the amount of reactants used is the same as that of the product.

The total mass of the products must give us 125g according to this law of conservation of matter.

Now to find the masses of each product,

  1. Find the number of moles of the given reactant:

     Number of moles  = \frac{mass}{molar mass}

  molar mass of  KClO₃  = 39 + 35.5 + 3(16)  = 122.5g/mol

    So number of moles of KClO₃ = \frac{125}{122.5}  = 1.02moles

    2. Now, using this number of moles, find the number of moles of the products using this value;

   2 moles of KClO₃ produced 2 moles of KCl

  1.02 moles of KClO₃ will also produce 1.02moles of KCl

   2 moles of KClO₃ produced 3 moles of O₂

   1.02 moles of KClO₃ will produce   \frac{1.02 x 3} {2} mole = 1.53 moles of O₂

   3. Now find the masses of each product;

Mass  = number of moles x molar mass

  molar mass of KCl  = 39 + 35.5 = 74.5g/mol

  molar mass of O₂  = 16 x 2  = 32g/mol

  Mass of KCl  = 74.5 x 1.02  = 75.99g

  Mass of O₂  = 32 x 1.53 = 48.96g

Total mass of products = mass of KCl + Mass of O₂ = 75.99g + 48.96g

                                        = 124.95g

This value is approximately the same as that of mass of  KClO₃

 

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