Question

calculate the speed of an electron if its de broglie wavelength is twice its displacement in one second

Answer 1

Answer:

The speed of an electron is 0.01908 m/s.

Explanation:

De-Broglie wavelength is given by:

$\lambda=\frac{h}{mv}$

where,  $\lambda$ = wavelength of a particle

h = Planck's constant = $6.626\times 10^{-34}Js$

m = mass of particle

v = velocity of the particle

Velocity of an electron = v

Mass of an electron = $9.1\times 10^{-31}kg$

Wavelength of electron is twice the displacement in seconds which is velocity of an electron.

Then.wavelength of an electron = $\lambda =2v$

$\lambda =2v=\frac{6.626\times 10^{-34}Js}{9.1\times 10^{-31}kg\times v}$

v = 0.01908 m/s

The speed of an electron is 0.01908 m/s.