Answer:
160.86 g to the nearest hundredth.
Explanation:
H2 + O ---> H2O
2.016 g H2 produces 18.016 g H2O
1g .. .. .. .. .. 18.016 / 2.016 g H2O
18g .. .. .. .. .. . . (18.016 * 18) / 2.016 g H2O.
= 160.86 g.
Answer:
Option(II) and option (IV) are correct.
Explanation:
Here products are 
and 
and reactant is 
(I) According to Le-chatelier principle,increase in will shift the equilibrium towards reactant side to keep the equilibrium constant unchanged.
(II) According to Le-chatelier principle,decrease in will shift the equilibrium towards product side to keep the equilibrium constant unchanged.
(III) Adding a catalyst will not change position of equilibrium. Catalyst only helps to achieve equilibrium in a lesser time.
(IV) As this reaction is an endothermic reaction therefore heat is consumed in formation of product. Therefore increase in temperature will lead to formation of more product to consume excess heat added.
(V) Pure solids and liquids do not affect position of equilibrium as their concentrations remain unchanged.
True
Explanation:
In the electron dot notation, the two dots on Be represents valence electrons in the s-sublevel.
The electron dot notation is also known as lewis dot structure.
This notation shows only the chemical symbol surrounded by dots to represent the valence electrons.
The dots are arranged at the four sides of the symbol in pairs called lone pairs. The unpaired ones are the odd electrons.
For Be, the structure is 1s² 2s²
The 2s sublevel is in the outermost/valence shell and it is made up of two electrons.
It is correct to say that the two dots on Be denotes the valence electrons in the s-sublevel.
learn more:
Lewis structure brainly.com/question/6215269
#learnwithbrainly
Explanation:
Start with a balanced equation.
2H2 + O2 → 2H2O
Assuming that H2 is in excess, multiply the given moles H2O by the mole ratio between O2 and H2O in the balanced equation so that moles H2O cancel.
5 mol H2O × (1 mol O2/2 mol H2O) = 2.5 mol O2
Answer: 2.5 mol O2 are needed to make 5 mol H2O, assuming H2 is in excess.
