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Lynna [10]
2 years ago
13

Solve. m - 15 = 20 m =

Mathematics
2 answers:
Fittoniya [83]2 years ago
7 0

\text{Hello There!}

\text{We are going to need to isolate the variable}

m - 15 = 20

\text{Add 15 to both sides.}

\text{We do this because we need to perform inverse operations to find} \text{the value of the variable.}

m - 15 + 15 = 20 + 15 = 35

\fbox{Therefore, your answer is going to be 35.}

\rule{300}{1.5}

Vladimir [108]2 years ago
4 0

Answer:

35 i guest

Step-by-step explanation:

idk ?????????

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Someone plz help on # 15 (idk what to do) :/
aleksklad [387]

Answer:

2x-5= -20

move -5 to the other side

sign changes from -5 to 5

2x-5+5= -20+5

2x= -15

divide by 2 for both sides

2x/2= -15/2

cross out 2 and 2, divide by 2 and 2 and then becomes x

x= -15/2

4 0
3 years ago
What is -3i-4=i+3 in
lara31 [8.8K]

Answer:

-3i - 4 = i + 3

-3i - i = 3 + 4

-4i = 7

i = 7/-4 or -7/4

6 0
3 years ago
Which graph represents the solution to this inequality? -1/4(12x+8)<2x+11​
bekas [8.4K]

Answer:

C

Step-by-step explanation:

3 0
2 years ago
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The cost of 6 movie tickets is $57.00. What is the cost of 8 movie tickets?
Rudiy27

Answer:

Step-by-step explanation:

57 divided by 6 = 7.5

9.5  x  8 = $76

7 0
2 years ago
A survey found that​ women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also
Effectus [21]

Answer: 99.51%

Step-by-step explanation:

Given : A survey found that​ women's heights are normally distributed.

Population mean : \mu =63.2  \text{ inches}

Standard deviation: \sigma= 2.4\text{ inches}

Minimum height = 4ft. 9 in.=4\times12+9\text{ in.}=57\text{ in.}

Maximum height = 6ft. 2 in.=6\times12+2\text{ in.}=74\text{ in.}

Let x be the random variable that represent the women's height.

z-score : z=\dfrac{x-\mu}{\sigma}

For x=57, we have

z=\dfrac{57-63.2}{2.4}\approx-2.58

For x=74, we have

z=\dfrac{74-63.2}{2.4}\approx4.5

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

P(-2.58

Hence, the percentage of women meeting the height requirement = 99.51%

8 0
3 years ago
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