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2 years ago

Solve. m - 15 = 20 m =

Mathematics

2 answers:

Fittoniya [83]2 years ago

7 0

$\text{Hello There!}$

$\text{We are going to need to isolate the variable}$

$m - 15 = 20$

$\text{Add 15 to both sides.}$

$\text{We do this because we need to perform inverse operations to find}$ $\text{the value of the variable.}$

$m - 15 + 15 = 20 + 15 = 35$

$\fbox{Therefore, your answer is going to be 35.}$

$\rule{300}{1.5}$

Vladimir [108]2 years ago

4 0

Answer:

35 i guest

Step-by-step explanation:

idk ?????????

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The fox population in a certain region has a continuous growth rate of 5% per year. It is estimated that the population in the y

kvasek [131]

Answer:

P(t) = A * (1 + r)^t ;

14,922 ;

Year 2013

Step-by-step explanation:

Given the following :

Continuous growth rate(r) = 5% = 0.05

Population in year 2000 = Initial population (A) = 10,100

Time(t) = period (years since year 2000)

Find a function that models the population,P(t) , after (t) years since year 2000 (i.e. t= 0 for the year 2000).

P(t) = A * (1 + r)^t

Trying out our function for t = year 2000, t =0

P(0) = 10,100 * (1 + 0.05)^0

P(0) = 10,100 * 1.05^0 = 10,100

B.)

Use your function from part (a) to estimate the fox population in the year 2008.

Year 2008, t = 8

P(8) = 10,100 * (1 + 0.05)^8

P(8) = 10,100 * 1. 05^8

P(8) = 10,100 * 1.4774554437890625

= 14922.29

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c) Use your function to estimate the year when the fox population will reach over 18,400 foxes. Round t to the nearest whole year, then state the year.

P(t) = A * (1 + r)^t

18400 = 10,100 * (1.05)^t

18400/10100 = 1.05^t

1.8217821 = 1.05^t

1.05^t = 1.8217821

In(1.05^t) = ln(1.8217821)

0.0487901 * t = 0.5998151

t = 0.5998151 / 0.0487901

t = 12.293787

Therefore eit will take 13 years

2000 + 13 = 2013

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<h3>Formula to use</h3>

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aleksklad [387]

Answer:

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Step-by-step explanation:

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