Question

What is the smallest, positive integer value of x such that the value of f(x) = 2x + 3 exceeds the value of g(x) = 50x + 5?

Answer 1

F(x) > g(x)
2^x + 3 > 50x + 5

for x = 3 , f(3) > g(3)
11 > 155 (false)

for x = 10 , f(10) > g(10)
1027 > 505 (true)

for x = 9 , f(9) > g(9)
515 > 455 (true)

for x = 8 , f(8) > g(8)
259 > 405 (false)

the smallest,positive integer value of x is 9 since the value of 9 is the last number to exceeds g(x)