If the points (-3,2),(4,-4) are joined to form a straight line, at what point does the line intersect the y-axis

1 answer:

7 0

Construct the line using the two points:
slope: m = (-4 - 2) / (4 + 3) = -6/7;
then, y = mx + b => 2 = (-6/7)(-3) + b => 14/7 - 18/7 = b => b = -4/7.
And your y-intersect is -4/7.

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$3\sqrt{3} + 72$

Step-by-step explanation:

I attached an image to aid the understanding of the question.

Looking at the image, we see that the 8 shaded parts are congruent, as affirmed in the question as well. And we are told that T = 3, this implies that the area of the square with T as it's side is 9ft². Since all the 8 squares are congruenrt, it means each square has its area to be 9. Therefore, the total area of the 8 shaded squares will be:

$9 \times 8 = 72ft^{2}$

It remains the area of the shaded square with side S.

From the question, we have the following ratio:

$\frac{9}{S} = \frac{S}{T}[\tex]But[tex]\frac{9}{S} = \frac{S}{3}[\tex]Multiplying through by 3S we have27 = S² and this gives:[tex]S = \sqrt{27} = 3\sqrt{3}$