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Natasha_Volkova [10]
3 years ago
6

Can someone please help me with this?​

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
7 0

Answer:

False

Step-by-step explanation:

Premise: 8n-1 = 2n+8

6n-1 = 8

6n = 9

n = 1.5 Since n must be an integer, this is an extraneous solution. The premise is false.

Scorpion4ik [409]3 years ago
5 0

Answer:

true 8 is the common

please follow me so I will follow you

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What is the range of these wages £140 £525
ELEN [110]
140-525 would be the range
4 0
2 years ago
Cole spent a total of 523.46 on holiday gifts for his friends and family. If he bought gifts for eleven people,about how much di
Vlada [557]

Answer:

Cole spend 47.587 on buying gifts for each person.

Step-by-step explanation:

Given:

Total money spend on gifts = 523.46

Number of people gifts were bought for = 11

We need to find how much he spend on each person.

Solution:

To find how much he spend on each person we will divide total money spend on gifts with number of people gifts were bought for.

framing in equation form we get;

Spending on each person = \frac{523.46}{11} = 47.587

Hence Cole spend 47.587 on buying gifts for each person.

6 0
3 years ago
I need help understanding how to do the problem
notsponge [240]
So.. if you notice the picture below

is really just 3/4 of a cylinder, or, a full cylinder, and then you slice 1/4 off of it
notice the right-angle in your picture at the bottom, is cut at a right-angle, meaning, the cutout is 1/4 of the volume

so \bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\qquad 
\begin{cases}
r=radius\\
h=height
\end{cases}\qquad \frac{3}{4}\textit{ of that}\implies \cfrac{3}{4}\cdot \pi r^2 h

4 0
3 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0
2 years ago
Mr. Whitman gave a test to his 32 math students. He felt the results were low, so he retested them one week later. The results o
Liono4ka [1.6K]

The number of student more passed the retake, when the students need a 65 in order to pass the test is 8.

<h3>What is box and whiskers plot?</h3>

Box plot is the way of representation of data which gives the graphical image of the data set to understand better. In this the data is represented with the help of quartile.

  • A.The difference in the median grade-

The median of first test is 60 while the second test is 80. Thus, the difference is,

d=80-60\\d=20

  • B. Compare the percent of students who got at least a 60 on the original test to those that got at least a 60 on the retake.

The student, who got at least 60 in first test, falls in the second half of the plot. Thus, the 50% of students got atleast 60% marks. In the retake test, all 100% student got at least 60 on test.

  • C. If the students need a 65 in order to pass the test, how many more passed the retake?

In the first test 1/4 are passed while in second test 3/4 students are passed and got the marks 65 or more than this, Thus the number of student pass more in this test,

n=(\dfrac{3}{4}-\dfrac{1}{2})\times 32\\n=8

Thus, the number of student more passed the retake, when the students need a 65 in order to pass the test is 8.

Learn more about the box and whiskers plot here;

brainly.com/question/9559392

#SPJ1

8 0
2 years ago
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