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Solnce55 [7]
2 years ago
13

Use the distributive property to find the product of 7 × 14.6. 98.6 102.2 21.6 98.42

Mathematics
1 answer:
umka2103 [35]2 years ago
5 0

Answer:

98.42

Step-by-step explanation:

7 × 14.6 =

= 7 × (7 + 7 + 0.6)

= 7 × 7 + 7 × 7 + 7 × 0.6

= 49 + 49 = 0.42

= 98.42

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Check the attached file for the answer.

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3 years ago
Find the equation of the line using the given information.
Alecsey [184]

When the slope is zero, the line is horizontal. Its equation will be of the form

... y = constant

The y-value of your point is specified as -9, so the equation of the line through that point is

... y = -9

8 0
3 years ago
Hello could you help me please?
Ilya [14]

Answer:

C. 6

Step-by-step explanation:

So it says read less thann 25 books --> that means the numbers are 13,14,14,16,19,21,21,22,23, and 24 --> a total of 10 numbers

Then it says read more than 35 books --> that means the numbers are 37,41,42,43 --> a total of 4 numbers

Now, it says how many more --> that means you subtract 4 by 10 = 10 - 4 = 6

Therefore the answer is 6 more students read less than 25 books than read more than 35 books.

3 0
2 years ago
Read 2 more answers
State the domain and range<br> {(2,4), (3,7), (4,9), (6,11)}
mihalych1998 [28]

Answer:

Domain= 2,3,4,6

Range=4,7,9,11

or

Domain [2,6]

Range [4,11]

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a
natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= \frac{x_1 +x_2 +...x_2_3}{23}

= 2.3hr

⇒\sum xi =2.3 \times 23 = 52.9hrs

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  = \frac{x_1 +x_2 +...x_2_3}{23}

\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47

therefore, the new sample mean is 2.47

2) For the old data set

the median is x_1_2(th) values

[\frac{n +1}{2} ]^t^h value

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = [{x_1_2]^t^h value remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)

The new sample standard sample deviation is calculated as

= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0
3 years ago
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