<h3>I'll teach you how to solve sqrt 150</h3>
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sqrt 150
Prime factorization:
sqrt 2*3*5^2
Apply radical rule:
sqrt 2*3 sqrt 5^2
Apply radical rule:
sqrt 2*3 *5
Multiply the numbers:
Your Answer Is (C)
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A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:
5 1/3 / 7 1/3 = 0.7272
Now rewrite the fraction as decimals:
2/3 = 0.667
¾ = 0.75
5/9 = 0.555
The closest scale that would still fit the frame would be 2/3 because it is under 0.727.
B. How much extra space is there in the frame when she uses the reduction from Part A?
Multiply the original size by the scale factor to use:
7 1/3 x 2/3 = 4 8/9
Now subtract the scaled size from the original size:
7 1/3 – 4 8/9 = 2 4/9 inches extra
C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?
Convert the scale from part A to a fraction:
0.72 = 72/99 which reduces to 8/11
Answer:
(8, -7)
Step-by-step explanation:
well since it flip over the x-axis only, the 8 stays the same, however, the 7 flips completely to the second quadrant and becomes -7.
Hope this helped and have a amazing day.
Answer:
its the last one
Step-by-step explanation:
