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Aneli [31]
3 years ago
15

Find the missing length Indicated

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

60

Step-by-step explanation:

x² = 144×25

= 3600

x =√3600 =60

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Mika rides his bike 3 miles each way to his friend's house. He leaves his house at 4 p.m. How many miles does he ride his bike t
Anettt [7]

Answer: Mika rides his bike for 6 miles to his friend's house and back. The extra information is when the problem says "He leaves his house at 4 p.m." since we are talking about distance, not time.

Step-by-step explanation:

3 0
3 years ago
Rationalize the denominators
SpyIntel [72]

Answer:

16

Step-by-step explanation:

mult by root three and root 2

2 root 3 turns into 6

5 root 2 turns into 10

the bottom is now 3-2 so it is one

4 0
3 years ago
What percent increase is 1/3 to 1/6
r-ruslan [8.4K]

Answer:

50% increase

Step-by-step explanation:

half of 6 is 3 thus 50%, and vise versa.

4 0
2 years ago
What are the odds of choosing a red marble from a bag that contains two blue marbles, one green marble and four red marbles?
Ierofanga [76]

Answer:

4/7.

Step-by-step explanation:

This the question in which marbles have to be taken out of a bag. Odds in another word for probability.

Total number of marbles in the bag = 2 Blue + 1 Green + 4 Red = 7 marbles.

Required marbles = 3 red marbles.

Therefore:

P (a red marble is selected in the first attempt) = Red Marbles / Total Marbles.

P (a red marble is selected in the first attempt) = 4/7.

Therefore, the correct answer is 4/7!!!

8 0
3 years ago
Any help with an explanation would be appreciated!
Lilit [14]

Problem 1

We'll use the product rule to say

h(x) = f(x)*g(x)

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

Then plug in x = 2 and use the table to fill in the rest

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)

h ' (2) = 2*3 + 2*4

h ' (2) = 6 + 8

h ' (2) = 14

<h3>Answer: 14</h3>

============================================================

Problem 2

Now we'll use the quotient rule

h(x) = \frac{f(x)}{g(x)}\\\\h'(x) = \frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}\\\\h'(2) = \frac{f'(2)*g(2)-f(2)*g'(2)}{(g(2))^2}\\\\h'(2) = \frac{2*3-2*4}{(3)^2}\\\\h'(2) = \frac{6-8}{9}\\\\h'(2) = -\frac{2}{9}\\\\

<h3>Answer:  -2/9</h3>

============================================================

Problem 3

Use the chain rule

h(x) = f(g(x))\\\\h'(x) = f'(g(x))*g'(x)\\\\h'(2) = f'(g(2))*g'(2)\\\\h'(2) = f'(3)*g'(2)\\\\h'(2) = 3*4\\\\h'(2) = 12\\\\

<h3>Answer:  12</h3>
5 0
2 years ago
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